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Mathematics: Post your doubts here!
ohh okay so u substituted it.. cool.. so easy n i couldn't even see it..... so what is the difference when the question says ' write down the number o roots' and ' deduce the number of roots' ? when the interval changes to 10pi<= (theta)<=20pi what do i do? do i draw another graph? -
Mathematics: Post your doubts here!
right finallyyyy getting the hang of it- thank you -
Mathematics: Post your doubts here!
so the roots are the four roots shown on the diagram- which is unclear because i am not using a graphing paper- btw changing the scale from radians to degrees is allowed in exams? and the roots i asked for was for 2cos(2 theta) - 1= 0 not cos(2 theta) and y= 1/2 after which i have... -
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Mathematics: Post your doubts here!
thnak you- working late night, with u all helping give me courage, thnx -
Mathematics: Post your doubts here!
so after integrating it i get x^2 - 6x + C is that correct? -
Mathematics: Post your doubts here!
if i do that i get 2x-6=0, 2x=6, x=3 so 3 is the x value which will give a stationary value and what about the integral i asked about if you want to change f '(x) back into f (x) how would you have done it- i got x^2-6x +c as the answer -
Mathematics: Post your doubts here!
i thought f ' (x) gave us the gradient of the tangent line not the stationary point? -
Mathematics: Post your doubts here!
when you are given f ' (x) as 2x-6 and that the range of function f(x)>= -4 and you have to find the value of x for which f(x) has a stationary value, do you differentiate the f ' (x) agn so that you get f '' (x)= 2 ... then would 2 be the answer? and to find the original function from f ' (x)... -
Mathematics: Post your doubts here!
Thanks that clears my confusion -
Mathematics: Post your doubts here!
i know but it takes up my time in my practice exams that's why n sometimes it says ascending power of x or descending power of x- how do u figure out whether you start with 6C6 or 6C1? -
Mathematics: Post your doubts here!
isnt there a simpler way of doing it- writing out all the terms in my test will take me ages? but this is really helpful.... thank u -
Mathematics: Post your doubts here!
Need help with this as well (please draw and show as well) i) sketch on a single diagram the graphs of y-cos2(theta) and y=1/2 for 0<= (theta)=<2(pi) ii) write down the number of roots of the equation 2cos2(theta) - 1=0 in the interval 0<= (theta)=< 2(pi) iii) deduce the number of... -
Mathematics: Post your doubts here!
Please help with this. urgent- please explain you steps find the term independent of x in the expansion of (2x+ 1/x^2)^6 its 3 marks from paper 1 of oct nov 2011 unfortunately i dnt have a link cos i have on hard copy sorry please help out -
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Mathematics: Post your doubts here!
this is how you solve it area of rectangle= length *width so you have to multiply both side out (2x+3)*(x+1)= 2x^2 +5x+3 from this equation you set the outcome to 10cm^2 and 36cm^2 so you have 2x^2 + 5x+3=10 2x^2 +5x-7=0 2x^2+5x+3= 36 2x^2+5x- 33= 0 now you solve both equation for x... -
Mathematics: Post your doubts here!
Hi i need help with this question Relative to the origin O the point A has a poistion vector 4i+7j-pk and the point B has a position vector 8i-j-pk, where p is constatnt i) Find OA.OB ii) hence show that there are no real values of p for which OA and OB are perpendicular to each other iii)... -
Mathematics: Post your doubts here!
Hi i have another question on binomial expansion find the term independent of x in the expansion of (2x+ 1/x^2)^6 its 3 marks from paper 1 of oct nov 2011 unfortunately i dnt have a link cos i have on hard copy sorry -
Mathematics: Post your doubts here!
Thanks agn- so i was right just my methods slightly different. thank you!!!!!!!! -
Mathematics: Post your doubts here!
You don't have to set both the equations equal to each other. You'll rearrange the equation of the line so as it'll become an expression for 'x' in terms of 'y'. 2y + x = k x = k - 2y Replace 'x' with 'x = k - 2y' in the curve equation. y^2 + 2x = 13 y^2 + 2 (k - 2y) = 13 y^2 + 2k - 4y - 13...