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  1. D

    They're going okay. How was yours?

    They're going okay. How was yours?
  2. D

    Not interested anymore. Will try for University of Melbourne, Delft, or Imperial.

    Not interested anymore. Will try for University of Melbourne, Delft, or Imperial.
  3. D

    Netherlands. BSc in Chemical Engineering, then I'll go back to Australia and apply for the MEng...

    Netherlands. BSc in Chemical Engineering, then I'll go back to Australia and apply for the MEng in Chemical Engineering. Then I'll try for a PhD in Chemical Engineering and Nanomedicine.
  4. D

    Hey, I'm curious. What's your plan after the A levels?

    Hey, I'm curious. What's your plan after the A levels?
  5. D

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    Okay, first, you have to realize that X cannot be a cyclic compound. Why? Because the NH group in coniine is the reason the compound is cyclic. In its absence, the compound is a straight chain. Now notice one thing. When 'N' is removed, that leaves two ends, which is originally occupied by the...
  6. D

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    No, lambda/2 is used for adjacent nodes. The two nodes in the question are not adjacent.
  7. D

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    I don't know how else to explain it. Sorry.
  8. D

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    No, it's just logic.
  9. D

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    To find the number of periods between two points, you have to divide the total distance by the wavelength. In this case, the wavelength is 0.3 m, and the distance is 0.45 m.
  10. D

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    Since this is an EM wave, its speed is 3x10^8 ms^-1. Frequency is 1GHz= 1 000 000 000 Hz. Use v = fλ. Therefore, λ = 0.3m. Distance = 45 cm = 0.45 m. Periods present b/w the transmitter and the plate = 0.45/0.3 = 1.5. In a stationary wave, 1 period contains 2 antinodes. Therefore, half a...
  11. D

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    No problem :)
  12. D

    Last minute preparation on MCQS 9701 and 9702. Discussion here.

    2^n is for the number of isomers. They can be cis-trans, chain, position, blah blah blah. I think this formula is dependant upon the nature of the compound, and I have tried it with various compounds, and it seems to work so far. Let me elaborate. In this case, since the compound is symmetrical...
  13. D

    How was 9709_w15_qp_62?

    It was 316. I'm absolutely sure.
  14. D

    How was 9700 W15 paper 34?

    I'm not sure. Just hope for the best.
  15. D

    How was 9700 W15 paper 34?

    Maybe, maybe not. I drew a bar graph, so I'm not sure either. Uh..not sure either. You might lose 4 marks max, but who knows.
  16. D

    How was 9702 W15 paper 22?

    But 22 never crossed 40 ;)
  17. D

    How was 9702 W15 paper 22?

    I did it by drawing and got 12.2 or 12.1
  18. D

    How was 9702 W15 paper 22?

    Anyway, I don't want an A. I just want a B in physics :D
  19. D

    How was 9702 W15 paper 22?

    I used Kirchoff's law to explain that xD
  20. D

    How was 9702 W15 paper 22?

    It won't, trust me.
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