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Search results

  1. AbbbbY

    Mathematics: Post your doubts here!

    Are you talking about Q8 of the paper? The one with f''(x) given and asking for the other turning point?
  2. AbbbbY

    Chemistry: Post your doubts here!

    Definitely the former. Recent P2's have been much more challenging. Anyway. The Organic will help you in P4. They might not have asked a lot of the reactions now but A2 organic is A2 inside the ring and AS outside it.
  3. AbbbbY

    Chemistry: Post your doubts here!

    I think NO2 (?). It's a brown gas. The test tube turns brownish on the inside. It's given on the last page btw so just cross check from that. O2 -> Relights a glowing splint H2 -> Burning splint goes off with a pop CO2 -> Turns limewater milky What I usually advise people is to briefly smell...
  4. AbbbbY

    Chemistry: Post your doubts here!

    Nope. Just asked for the Ar.
  5. AbbbbY

    Chemistry: Post your doubts here!

    A vast percentage of your grade is P4 so you can even get an A* if you ace that.
  6. AbbbbY

    Chemistry: Post your doubts here!

    10.8 If you used fractions, yes. If you used decimals, no. Al2O3 + NaOH -> NaAlO2 + H2O The first step of this is also acceptable, in that, Al2O3 + NaOH -> Al(OH)3 + Na I don't think. Ecf doesn't come into play here. Usually.
  7. AbbbbY

    Chemistry: Post your doubts here!

    Has to be the easiest P2 I've seen in a long time. Calculations were easy as was the organic. Infact, organic on this paper was childsplay tbh. Recent papers have had so much tougher organic questions.
  8. AbbbbY

    Chemistry: Post your doubts here!

    You've reacted Acid + Alcohol + HCl to give you an ester. At equilibrium, some unreacted acid, unreacted alcohol HCl and the ester is present. You react this with NaOH (Lets assume the ester is NOT hydrolysed here). The NaOH will react completely with HCl and the remainder will react with the...
  9. AbbbbY

    Chemistry: Post your doubts here!

    Arguably the easiest P2 I've come across ever! How'd everyone's paper go?
  10. AbbbbY

    Chemistry: Post your doubts here!

    Umm. What is NaOH and can it even have a ph < 7. Think, my dear Watson, think. Even a first year OLevels student knows the pH of NaOH as I'm sure do you.
  11. AbbbbY

    Football/Soccer anyone?

    And the interim boss indeed shows them how it's done. Giggsy with a beauty assist. Super control trough to RvP who scores on the rebound. Honesty this game looks more of a Giggs/Vidic friendly testimonial than a league game lol.
  12. AbbbbY

    Football/Soccer anyone?

    "The manager is coming on to show the kids how it's done" Lol moment. Though, Old Trafford is wildd!! Would've loved to have been there.
  13. AbbbbY

    Chemistry: Post your doubts here!

    Hahh. Same here. I fear what awaits in Math and Physics for me. I have yet to read a word of Physics Applications + I'm not too fond of P3 + I don't know normal distribution. :[ I would, instead of doing the aforementioned, spend more time reading on absolutely useless topics of Chem going into...
  14. AbbbbY

    Chemistry: Post your doubts here!

    I see. But my problem was primarily NaOH. Which one of them would form? Why not? You're one of the few that I've seen here with a really, really strong grasp on concepts
  15. AbbbbY

    Chemistry: Post your doubts here!

    I'm only human, you know.
  16. AbbbbY

    Chemistry: Post your doubts here!

    Okay people. Just a little confusion I've got left. Could you guys let me know all the reagents that'd give each of 1, 2 and 3. Also, let me know if any of the 3 is not possible. Namehere Suchal Riaz
  17. AbbbbY

    Chemistry: Post your doubts here!

    Lol. How exactly would that work? :p The peaks vary depending on the compound and the shift depends on the environment.
  18. AbbbbY

    Chemistry: Post your doubts here!

    I was practicing P4's and I just came across this. Why would it pop up in AS if it's in P4 :/
  19. AbbbbY

    Chemistry: Post your doubts here!

    Easy question. Been asked here quite a lot recently. Look, moles of NaOH used = 0.045 Moles of NaOH that react with HCl = 0.005 The remaining NaOH is what reacted with the acid so acid remaining = 0.040 Equilibrium concentrations = 0.04 0.04 0.06 0.06 If you don't get the abridged...
  20. AbbbbY

    Chemistry: Post your doubts here!

    So then where did you get this question. It has insufficient detail. I believe the full question will have something to do with graphite.
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