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  1. thementor

    Mechanics 1 P42 2014; Discussion!

    yes
  2. thementor

    Mechanics 1 P42 2014; Discussion!

    Will you be posting other solutions as well?
  3. thementor

    9709 MATHEMATICS P42 2014 GT

    WHAAT?
  4. thementor

    Mechanics 1 P42 2014; Discussion!

    awesome thankssssssssss
  5. thementor

    Mechanics 1 P42 2014; Discussion!

    1/ (sqrt(3))
  6. thementor

    Mechanics 1 P42 2014; Discussion!

    hahaaha. Hyper memory syndrome lol. And yayyyyy thanks.
  7. thementor

    Mechanics 1 P42 2014; Discussion!

    The 5kg one was resting on the slope. The 16 kg one was hanging from the pulley.
  8. thementor

    Mechanics 1 P42 2014; Discussion!

    you still have a chance at an A*. If you're chances go, then what about me? :( I made a lot of mistakes in Q5?
  9. thementor

    Mechanics 1 P42 2014; Discussion!

    cheer up :)
  10. thementor

    Mechanics 1 P42 2014; Discussion!

    no worries. Still you get marks for the correct method,.
  11. thementor

    Mechanics 1 P42 2014; Discussion!

    A car of mass 600 kg is travelling along a horizontal road where the resistance to motion is constant and equal to R. The acceleration is 1.4 at a point when the power of the engine is 22.5kW and the speed of the car is 18/ Find R
  12. thementor

    9709 MATHEMATICS P42 2014 GT

    YIPIEEEEEEEE! :p Can I ask just one thing? The particles were travelling in opposite directions right?
  13. thementor

    Mechanics 1 P42 2014; Discussion!

    Yupp. See the mass of the car was 600kg and the acceleration was 1.4 and the Power given to you was 22.5 kW. and v=18
  14. thementor

    9709 MATHEMATICS P42 2014 GT

    What about Q1? F was 410 right?
  15. thementor

    9709 MATHEMATICS P42 2014 GT

    4.98? 0.O
  16. thementor

    Mechanics 1 P42 2014; Discussion!

    Man after hearing your answers I can relax. Q7 (I) TA = 0.25a +2.5, TB = 7.5-0.75a (ii) a= 2 show (iii) 1.2 ms^-1 (iv) -6 ms^-2 or simply the magnitude of the deceleration was 6
  17. thementor

    Mechanics 1 P42 2014; Discussion!

    P was 6150W because at constant speed the forward force will be equal to the resistive force. So using P =FV, where F=410 and v=15
  18. thementor

    Mechanics 1 P42 2014; Discussion!

    T=17.59 yessss :P
  19. thementor

    9709 MATHEMATICS P42 2014 GT

    J13 was easyyyy. I got a perfect 50 when I attempted that paper
  20. thementor

    9709 MATHEMATICS P42 2014 GT

    Particle A is travelling from A at an acceleration of 0.5 ms^-2 and has started from rest. Particle Q passes through B and is travelling at a constant speed of 0.75 ms^-1 .They collide at time T. Find the value of T
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