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  1. hellodjfos;s'ff

    Physics: Post your doubts here!

    Yup really helpful in maths A1. You don't even need to practice for p1 if you had taken add maths in o-level.
  2. hellodjfos;s'ff

    Physics: Post your doubts here!

    What about you? O-level and A-level subjects?
  3. hellodjfos;s'ff

    Physics: Post your doubts here!

    I don't know how to identify an extra subject since BDC Karachi encouraged us to take 9, but I took these in olevels: business, maths, add maths, chemistry, physics, urdu first language, english first language, pak studies, islamiyat. In a-levels i am taking: maths, physics, chemistry, psychology.
  4. hellodjfos;s'ff

    Physics: Post your doubts here!

    Yeah i know :/ I would have got an A* in that without putting in much effort
  5. hellodjfos;s'ff

    Physics: Post your doubts here!

    The papers were so easy. I couldn't have wished for easier papers
  6. hellodjfos;s'ff

    Physics: Post your doubts here!

    I got 8A* and 1A. I took urdu first language so I got an A in that... bad decision.
  7. hellodjfos;s'ff

    Physics: Post your doubts here!

    No worries :)
  8. hellodjfos;s'ff

    Physics: Post your doubts here!

    If you want additional reasoning: A and B are incorrect because we don't know the resistance of the resistors(or whether they are identical), so we can't determine their power loss(so A and B can't be justified). D is incorrect because again, the power produced by the cell is spread to overcome...
  9. hellodjfos;s'ff

    Physics: Post your doubts here!

    So the power produced by the cell is distributed to overcome the resistance of each resistor(this causes power loss). So the power produced by the cell is equal to the power lost in the resistors which is why C is the correct answer. 'Power output of the cell' just means the power produced by...
  10. hellodjfos;s'ff

    Physics: Post your doubts here!

    When the source of wave is travelling at a higher speed, the observed frequency rises(you can test this using values and the formula), so A and B are ruled out. When a source of wave approaches an observer, the observed frequency increases. So, initially the observer was detecting a microwave...
  11. hellodjfos;s'ff

    Physics: Post your doubts here!

    Because they gave the angle between the two first order maximum. The angle in the equation dsin(theta)=n(lamda) is the angle between the central maxima and the order, so to get this angle you divide 70 by 2 which is 35.
  12. hellodjfos;s'ff

    Physics: Post your doubts here!

    P=E/t, KE=1/2(m)(v^2), D=m/V m=D*V KE=1/2(D*V)(v^2) The volume is broken up into area and length P=1/2(D*A*l)(v^2)/t l/t=v, so: P=1/2(D*A*v^3) This gives an input power of 1300kW. Since the efficiency is 50%, the output power is 650kW, hence the answer B.
  13. hellodjfos;s'ff

    Physics: Post your doubts here!

    They're great but I don't like to show off.
  14. hellodjfos;s'ff

    Physics: Post your doubts here!

    Firstly, the ball is released meaning it's initial velocity(u) is zero. Now, you form two equations, one for the motion of the ball from zero point to m1, then from zero point to m2. First equation: u=o, s=x, a=finding, t=t1 s=ut+1/2(a)(t^2) x=1/2(a)(t1^2) --- 1st equation u=o, s=x+h...
  15. hellodjfos;s'ff

    Physics: Post your doubts here!

    The angle between the central maxima and first order is 35(which is the theta in the equation dsin(theta)=n(lamda) ) 1x10^-6*sin35=1(lamda) lamda=5.7x10^-7 which is 574nm(C)
  16. hellodjfos;s'ff

    Physics: Post your doubts here!

    Bro it is a VELOCITY-DISTANCE graph not a velocity-time graph. If it were a velocity-time graph, it would be B since the velocity is constant initially and then there is a constant deceleration(gradient is constant in that graph). But that's not the case. The answer would be A, because the car...
  17. hellodjfos;s'ff

    Physics: Post your doubts here!

    Only one field exists here which is electric. The electric field's direction is towards the right so the positive terminal is at the left and the negative terminal is at the right side. Since the electron is approaching the negative terminal, there would be a repulsion force. This would case the...
  18. hellodjfos;s'ff

    Physics: Post your doubts here!

    Ok this is a difficult question to understand. So the concept of this drink is that the child decreases the pressure on the top of the straw to 90% of the atmospheric pressure. This means there is a pressure difference between the air in the straw and the atmosphere of 10%. So the atmosphere...
  19. hellodjfos;s'ff

    Physics: Post your doubts here!

    Intensity is directly proportional to amplitude squared. The equation becomes I=A^2/x^2 which can be simplified to I=A/x At P: I=8/1 so intensity at P is 8 micro meter At Q: I=8/2 so intensity at Q is 4 micro meter(D)
  20. hellodjfos;s'ff

    Physics: Post your doubts here!

    I think there are about 3 methods to attempt this one. P=pgh, P=F/A F=P*A F=pgh*A g*h becomes v^2(their units multiply to form the units of v^2). F=p(v^2)(A) which is D 2nd method: F=mv/t, p=m/V, v=l/t p=m/V becomes m=p*V Replace m=p*V into F=mv/t F=p*V*v/t V can be broken up into A and l(area...
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