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  1. Metanoia

    Chemistry: Post your doubts here!

    solubility rules, BaSO4 is insoluble. Hmm.. Which reaction are you basing on when you mention barium sulfate and acid?
  2. Metanoia

    Chemistry: Post your doubts here!

    Can you type out the spdf configurations of the mentioned atoms? What values are you using? Chances are you didn't convert dm3 to m3.
  3. Metanoia

    Chemistry: Post your doubts here!

    Q16. Barium sulfate is not soluble in the acid, whereas barium carbonates reacts with the acid to form a soluble barium compound. Q26. X represents a halogen atom. W: CH3CH2XCH3 X: CH3CH(OH)CH3X Y: CH3CH2XCH3 Z: CH3CH2CH2OH
  4. Metanoia

    Chemistry: Post your doubts here!

    Q12 heat absorbed by 200 g of water = 200 x 4.2 x 48 = 40 320 heat released by 1.6 g of fuel = 40320/45 x100 = 89 600 heat released by 1 g of fuel = 89600/1.6 = 56 000 Q25. Option A can give both aldehyde and acid.
  5. Metanoia

    Chemistry: Post your doubts here!

    Thats the wrong answer? Which year is it?
  6. Metanoia

    Chemistry: Post your doubts here!

    Correct. Break the molecule and then oxidize the areas you've circled. See how many fragments you get that end up with a ketone group.
  7. Metanoia

    Chemistry: Post your doubts here!

    Where will the cleaving of the molecule occur?
  8. Metanoia

    Chemistry: Post your doubts here!

    Question is asking for number of fragment molecules containing the ketone group, not number of ketone groups.
  9. Metanoia

    Chemistry: Post your doubts here!

    You can try to create the 2 half equations 2HIO + 2H+ + 2e- --> I2 + 2H2O ------ (1) HIO -+ 2H2O -> HIO3 + 4H+ + 4e- ------ (2) Before combining the 2 equations, we need to make both equations have the same number of electrons (2) x 2 + (1) So ratio of I2 to HIO3 is 2: 1
  10. Metanoia

    Chemistry: Post your doubts here!

    Option says carboxyllic acid, not ethanoic acid.
  11. Metanoia

    Chemistry: Post your doubts here!

    The NH3 molecule is the same before and after the reaction, so we would not expect any change in its oxidation state. Ag+ + 2NH3 --> [Ag(NH3)2]+ If you do intend to calculate each atoms, you have to be careful. +1 + 2x + 6 = +1 ( you had -2x instead of +2x)
  12. Metanoia

    Chemistry: Post your doubts here!

    total moles = 1- x + 1 -x + x + x = 2 moles
  13. Metanoia

    Chemistry: Post your doubts here!

    Leaving mathematical calculations aside, we can reason it out in this manner. A <-> B exothermic can also be represented by A <-> B + heat A <-> B endothermic can also be represented by A + heat <-> B Changing the temperature (removing or adding heat) will shift the equilibriums...
  14. Metanoia

    Chemistry: Post your doubts here!

    You are referring to the line mole of H2 formed = 33.3/100 *2 ? The 2 is the total moles of gases, moles of H2 = % of H2 x total moles
  15. Metanoia

    Chemistry: Post your doubts here!

    You can post the answer scheme here for checking. This question is familiar, I believe it was answered before.
  16. Metanoia

    chemistry doubt

    K2O + H2O --> 2KOH ------- (1) 2KOH + H2SO4 --> K2SO4 + 2H2O ----(2) moles of H2SO4 used in (2) = conc x vol = 2 x 0.015 = 0.03 mol moles of KOH used in (2) = 0.03 x 2 = 0.06 mol Taking into account the dilution factor, moles of KOH in 250 cm3 = 0.06 x 10 = 0.6 mol moles of K2O = 0.6/2...
  17. Metanoia

    Chemistry: Post your doubts here!

    With such questions, the neatest approach would be to use the tables to keep track of the quantities of reactants and products.
  18. Metanoia

    Chemistry: Post your doubts here!

    Look at the molecules, which one of them is optically active (have a chiral carbon)? Look at the groups connected to the double bonds, which of them is showing the trans isomerism?
  19. Metanoia

    Chemistry: Post your doubts here!

    The carbon (in the alkane) that had its H replaced by Br is oxidized.
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