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Physics: Post your doubts here!
Ok so.... firstly, you need to look at the directions the forces are acting. BOTH forces are acting inwards onto the particle, as a result of this, the resultant force will also act inwards. The next step is figuring out the direction in which it acts, you can find this out by attaching the... -
Chemistry: Post your doubts here!
15:30:15 is the ratio for N: P :K in 100g. If the recommended usage is 14g of fertiliser, you need to change the ratios to match 14g. 15+30+15 = 60 NPK makes up 60g out of the 100g. So how much will it make in 14g? 60/100 = x / 14 This gives you 8.4g out of the 14g. 15:30:15 is in the ratio... -
Physics: Post your doubts here!
It all depends on which direction you consider the resultant force to act. However, this will If you find that you can manage calculations in a multiple choice exam, be my guest and use this method ^_^ -
Physics: Post your doubts here!
Each wave cycle is 360 degrees. You cannot just put the degrees where you want, you have to make sure each wave lasts a complete 360 degrees. Like so... Hope that made sense :) -
Physics: Post your doubts here!
Alright.. so for question 2, you need to find the torque. Torque is force x perpendicular distance between two forces. In that diagram you're already given the distance which is 0.30 m. However, the forces are not perpendicular, So you're going to want to find the vertical components. That is 2... -
Physics: Post your doubts here!
For Q8, regarding the ball. From X to Y, the ball accelerates uniformly till it reaches point Y, you could say that the weight of the ball is what's making it accelerate. When it passes Y, the ball is now on a horizontal surface, since weight acts vertically, the ball wont accelerate... -
Physics: Post your doubts here!
I think a hint lies within the word " net ". From what I know, net and resultant are one of the same. For example, when 3 N acts to the left and 4 N to the right, they say the net force/resultant force acting is 1 N to the right... Which leads me to believe that when they say net work done... -
Physics: Post your doubts here!
When you stretch a spring, we do work. If we then release the spring, some of the energy is recovered. Some is lost. When they say " net " work done, they're talking about the total work done. The arrows going up signify that the spring is being loaded, and thus we call it the loading phase... -
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Chemistry: Post your doubts here!
For 15, how do you figure out the ratio? How did you know it's 1:1? o_O -
Physics: Post your doubts here!
Well firstly. you need to look at all the data you already have. From (b), you've got the initial acceleration which is 0.570 ms^-2. You also have the constant velocity which is 2.00 ms^-1. You have the deceleration too, which you calculated to be 0.306 ms^-2. You already have the formula... -
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Physics: Post your doubts here!
No problem ^_^. Can't help with 33 and 34 yet as I still have to go over my theory with those. -
WHEN CAN WE DISCUSS ABOUT THE AICT P2 ?
Don't bother. The exam's over and there's nothing you'll be able to do to change your answers even if they do happen to be different from everyone else. Just believe in yourself and what you did and pray that it all went well. Focus on your remaining exams for now, don't stay fixated on what you... -
Physics: Post your doubts here!
There are keywords in every question that you have to be watchful for. Question 11 > The ball is falling at " terminal " speed in " still " air. Now the first thing to note is that if it's terminal, then the ball is not accelerating. With that in mind, you look at the three forces they mention... -
AICT applied ict help needed..!!!
Well I just attempted a paper earlier today and it only showed up on all my printouts after adding it to a label that I placed just above the field names. Not the one with the text unbound stuff... -
AICT applied ict help needed..!!!
For this very instance, I believe since we're dealing with values on 3 axes, that a line graph would be fit for purpose. Ideally when you're dealing with values on 2 axes, a bar chart would seem more viable. Oh and on that note, I need to tell you something regarding your doubt with the report... -
Physics: Post your doubts here!
I believe since the ball reaches a constant velocity then there'd have to be a force resisting the one pulling it down. Don't quote me a 100% on this, but I get the feeling that upthrust is a force pushing an object up rather than resisting a force acting down. And if it's pushing the object up... -
Applied ict 9713 paper2 (post your doubts here)
I sent you a PM. -
AICT applied ict help needed..!!!
For question 15, in the report design view or layout view, click on the group and sort ribbon on the top, then select what you wish to group by, click on the small arrow. There will be an option to include group footer or not include one. Change that to include group footer. Then click on...