• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Search results

  1. AbbbbY

    Chemistry: Post your doubts here!

    Oh my! Lovely! Wonder why I didn't see it as individual steps leading up to the slowest! Hah!
  2. AbbbbY

    Chemistry: Post your doubts here!

    Idk I just take somethign that fits on the divisions without awkward calculations, and something that has enough spread to cover 2/3rds of the graph. So, a slight overlap from the max value.
  3. AbbbbY

    Chemistry: Post your doubts here!

    Order wrt H2O2 = Order 1 Order wrt H+ = Order 0 A 0.07 0.05 1.4 B 0.09 0.07 1.8 I need to convert A to 0.09 0.05 1.4 to compare the two (or convert B to 0.07 0.07 1.8. Same thing). We know it's order 1. So, simply do this: 0.07 0.05 1.4 0.09 0.05 X 0.09/0.07 = X/1.4 X = 1.8 So order wrt...
  4. AbbbbY

    Chemistry: Post your doubts here!

    That's low enough to take real-axes x axis: I'd take 0 origin and 3 end. y axis: I'd take 0 origin and 5 or 6 end. 9 big black lines on the x axis, 12 on the y axis. X: 9/3 = 3 big boxes = 1.00 Y: 12/6 = 2 big boxes = 1.00 Not saying that everyone should use this, just showing how I do...
  5. AbbbbY

    Chemistry: Post your doubts here!

    Sorry just saw this. There are several, available, but in P5, due to common-lab equipment restrictions, we're to use 100cm3 gas syringes.
  6. AbbbbY

    Chemistry: Post your doubts here!

    It has an arene ring/benzene ring. Not a cyclic ring. Look at the 4 diagrams shown in the question! It blatantly states that benzene is co-planer.
  7. AbbbbY

    Chemistry: Post your doubts here!

    What are your max and min values for the x and y axis. Cba to calculate it all.
  8. AbbbbY

    Chemistry: Post your doubts here!

    Sorry for the delays. Got a bit busy + don't really like opening p5's, personally. __ 2biii: This is a pretty simple question with a horribly messed up wording. See. Collecting 30dm3 and 24dm3 is not possible with normal lab equipment. Collecting 10cm3 or 20cm3 is. We know that 1 mol = 123.5g...
  9. AbbbbY

    Chemistry: Post your doubts here!

    Will do in a lil while. A bit stuck up + I loathe P5's :p
  10. AbbbbY

    Chemistry: Post your doubts here!

    ON09 42 Q5a. I've answered this before a day or two ago but I'll do it again anyway. Look. This stuff isn't in the syllabus or taught. This is precisely why it has shown you the 4 figures above the actual question. The examiner wants you to analyze those figures, see whats going on, and apply...
  11. AbbbbY

    Chemistry: Post your doubts here!

    Q3: C A Charge on the cation is ruled out. Mg is 2+ and Na is 1+ yet they both have the same lattice. B Ratio of the ionic charges is ruled out. The ratio is the same for all three lattices. C NaCl = (102/181 = 0.56) MgO = ( 72/140 = 0.51) CsCl = (167/181=0.92). So definitely this. D Ruled...
  12. AbbbbY

    Chemistry: Post your doubts here!

    pH = pKa + lg([salt]/[acid]) (or pH = pKa - lg([acid]/[salt]) ) 5.5 = -lg(1.79 × 10^-5) + lg([Sa]/[A]) 5.5 - 4.75 = lg([Sa]/[A]) lg([Sa]/[A]) = 0.75 [Sa]/[A] = 10^0.75 [Sa]/[A]= 5.62 S = 5.62A A+S = 100 100-A=5.62A A = 15.1 = 15 So S = 85. Acid = 15, Salt = 85. Is this the answer? Edit...
  13. AbbbbY

    Chemistry: Post your doubts here!

    E is CH3COO- C is CH2OHCH(OH)COOH 4 bii, esterification will happen. Just make the ester. I can't write it down cos I can't show the branches via typing. If you don't get it, I can draw it and send a pic.
  14. AbbbbY

    Chemistry: Post your doubts here!

    Aye!
  15. AbbbbY

    Chemistry: Post your doubts here!

    My equation is intentionally unbalanced. All I wanted to show was the X(NO3)2 -> XO in a 1:1 And yes. Trial and error + quick calculator work will be quick too.
  16. AbbbbY

    Chemistry: Post your doubts here!

    Oh boy. That's a toughie. Group II metal nitrate upon heating will produce a metaloxide and NO2 in 1:1 X(NO3)2 -> XO + NO2 Umm. I'd probably tackle it by finding the mols of the metal nitrate and metal oxide in terms of x. 5/(x+(2(14+16*3)=5-3.29/(x+16) 5/x+124 = 1.71/x+16 5x+80 = 1.71x +...
  17. AbbbbY

    Chemistry: Post your doubts here!

    3 - D Na3- so gains 3 electrons. 1s2 2s2 2p6 5 B Hydrogen bonding exists b/w compounds containing N/O/F. 6 A Almost picked D overlooking ammonia but it'll be A bec ammonia has Hydrogen Bonding. 11 A? I'd go with A. OH- produced would react with the H+ ions added to form H2O again which...
  18. AbbbbY

    Chemistry: Post your doubts here!

    You're wrong there. They do run in opposite directions. I checked my notes to verify if I was mistaken.
  19. AbbbbY

    5- B. Hydrogen bonding exists in compounds containing N, O or F. With the exception of alpha...

    5- B. Hydrogen bonding exists in compounds containing N, O or F. With the exception of alpha helixes, which aren't in the AS syllabus. So yeah. NOF. Remember the word. 10- C Dissociates 50% in the ratio 1:2. meaning, at start 1 : 0 at equilibrium 0.5:1 so Kp =...
    • AbbbbY
    • Profile post comment
  20. AbbbbY

    Chemistry: Post your doubts here!

    Umm since they're beta pleated sheets, shouldn't they be running in opposite directions. I.e, CO under NH
Top