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  1. 6

    Physics /12 Discussion!

    yeah quite useful for playing tactical shooter games and for my part time job.
  2. 6

    Chemistry: Post your doubts here!

    first you find n(O2) the number of mol of oxygen we know that 1 mol of gas under standard condition occupies 24dm3 so 300cm3 O2 = 0.3/24 = 0.0125mol of O2 or 0.025mol of O since its a metal from group 1 or 2 so its either MO or M2O so mol number = mass/molar mass molar mass = mass/ mol number =...
  3. 6

    Physics /12 Discussion!

    Thanks I'm taking Physics, Chemistry, Biology, English Literature, Mathematics with Stats, Further Mathematics
  4. 6

    Physics /12 Discussion!

    thats actually just my goal last year when I took my A levels I only got 4 A* 1A, 1B 6A* is my goal this year!
  5. 6

    Physics /12 Discussion!

    so the model was 1/10 of original size we know that young modulus = stress/strain Y = (F/A)/(X/L) F=force, A=area, x=extension, L = original length Y = FL/AX X= FL/AY so the dimensions of the load is shrinked by 1/10, so volume is 1/1000. density is the same so mass is 1/1000 and weight...
  6. 6

    Physics /12 Discussion!

    you mean how answer is 10^2? im confused
  7. 6

    Physics /12 Discussion!

    the answer is 10^2 im pretty sure prep for chem is good P2 was alright, could be better.
  8. 6

    Chemistry: Post your doubts here!

    ok so there are 20cm^3 of O2 left, and 20cm^3 of SO2 formed, and 10cm^3 CO2 formed so total volume of gas is 20+20+10 = 50
  9. 6

    Physics /12 Discussion!

    its very hard, and havent taken chem yet oh and I had the crane question as well..
  10. 6

    Chemistry: Post your doubts here!

    iso propyl methanoate is like H-C=O | O | C - CH3 | CH3 and AB are wrong because molecular formula doesnt match, H is different
  11. 6

    Physics /12 Discussion!

    not yet, still 12hrs to go do you guys have a particularly tricky power question involving masses and a motor?
  12. 6

    Physics /12 Discussion!

    variance 13 was really hard as well. like really hard
  13. 6

    Troubles in chem p1

    C2H5OH + CH3CO2H ->CH3CO2C2H5 + H2O initial mol 1 1 0 0 equilibrium 1-x 1- x x x K = 4 = x^2/(1-x)^2 square root both sides 2 = x/(1-x) 2(1-x) = x 2-2x...
  14. 6

    Chemistry: Post your doubts here!

    #2 n(CS2):n(O2):n(CO2):n(SO2) = 1:3:1:2 so 10 cm3 of CS2 will react with 30cm3 of O2 leaving 20cm3 of O2 but this will form 10cm3 of CO2 and 20cm3 of SO2 so 20+20+10 = 50 then you add NaOH NaOH + CO2 -> NaHCO3 so all 10cm3 of CO2 disappears NaOH + SO2 -> NaHSO3 so all 20cm3 of SO2 disappears...
  15. 6

    Chemistry: Post your doubts here!

    s10 #21 answer is 3 remove H from 1st carbon on ethyl group remove H from 2nd carbon from ethyl group remove H from 1 of methyl group s12 qp11 #24 Answer is C, 4 esters methyl propanoate ethyl ethanoate propyl methanoate isopropyl methanoate s12 qp12 #28 question asking for name of...
  16. 6

    Chemistry: Post your doubts here!

    w09 #5 answer is B A is wrong because all the Cl balances out, nonpolar C is wrong because although molecule is not symmetrical, Cl and O have similar eletronegativity so small overall dipole D is wrong because its symmetrical nonpolar and O cancels out B is correct because not symmetrical and H...
  17. 6

    Chemistry: Post your doubts here!

    w05 #12 this is oxidation reactions forming oxides eg. 1 Mg + 0.5O2 -> 1MgO 1 Al + 0.75O2 -> 0.5Al2O3 1 S + 1O2 -> 1 SO2 because its in excess oxygen 1SO2 + 0.5 O2 -> 1SO3 so overall equation is 1S + 1.5O2 -> 1SO3 the oxidation ratio is 0.5:0.75: 1.5 = 2:3:6 =...
  18. 6

    Chemistry: Post your doubts here!

    #9 is bit hard to explain but aP -> bQ + cR initial mol 2 0 0 equilibrium mol 2-x(a/c)-(a/b)Y Y x we know that at equilibrium total mol is 2+x so 2 - x(a/c) - (a/b)Y +...
  19. 6

    P1 MCQ's preparation thread for chemistry ONLY!!!!

    draw the ions out – CH2CO2CH3, the hydrogen is lost from the ester group In B, it is a combination of ethanal with CH3CO2CH2- where the hydrogen is lost from the akyl group of the ester so it is not combined with – CH2CO2CH3
  20. 6

    Troubles in chem p1

    the 1:2 was oxidation number ratio 2:1 is molar ratio the overall net oxidation number change must be zero. so (-2) + 4 does not equal to 0 so you have to 2 x (-2) + 1 x (4) = 0 exam is coming soon.. just remember that mol ratio is inversely proportional to oxidation number ratio
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