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  1. amina1300

    Physics: Post your doubts here!

    The pressure must be constant.. nothing to explain .
  2. amina1300

    Physics: Post your doubts here!

    http://papers.gceguide.com/A%20Levels/Physics%20(9702)/9702_w16_qp_12.pdf Q4 , 10 26 ,29
  3. amina1300

    Physics: Post your doubts here!

    http://papers.gceguide.com/A%20Levels/Physics%20(9702)/9702_w16_qp_13.pdf Q16,13 ,29,24,25
  4. amina1300

    Chemistry: Post your doubts here!

    http://papers.gceguide.com/A%20Levels/Chemistry%20(9701)/9701_w16_qp_12.pdf Q30 Q26
  5. amina1300

    Chemistry: Post your doubts here!

    Q 11 20 29 http://papers.gceguide.com/A Levels/Chemistry (9701)/9701_w16_qp_13.pdf
  6. amina1300

    Physics: Post your doubts here!

  7. amina1300

    Physics: Post your doubts here!

    Ammeter reading = 0 P.D across junction = 0 P.D(R4) = P.D(R2 ) R4/(R3 + R4) * V = R2 /( R2 + R1 ) *V (R2 + R1)* R4 = R2 *(R3 + R4) R2R4 +R4R1 = R2R3 + R4R2 R4R1 = R2R3 AND = D
  8. amina1300

    Physics: Post your doubts here!

    SOMEONE EXPLAIN THIS QUESTION!! ANSWER = D
  9. amina1300

    Physics: Post your doubts here!

    selrey Which formula are you using? Post the methods you tried.
  10. amina1300

    Physics: Post your doubts here!

    F = ma F = m * v/t = density * Volume * v/t = p * A* l*v/t = p A v * l/t = pAv^2
  11. amina1300

    Physics: Post your doubts here!

    Im trying but all I get is 60655...Pa <_> SOMEONE SOLVE THIS QUESTION!!
  12. amina1300

    Physics: Post your doubts here!

    This is the hardest question!!! I spent a 5 hours trying to solve this! First we calculate the Total resistance : R2 = (R3 + R1) = [1+ 1/2]^-1 = 2/3 R5 + (R4 + 2/3 ) =[ 1 + 1 / (2/3 + 1)]^-1 = 0.625 0.625 + R6 = 1.675 ohm Total R = 1.675 ohm. Now we will use V= IR to calculate...
  13. amina1300

    Physics: Post your doubts here!

    p.d across 80 ohm resistor ; V= IR V = 1.2 * 80 = 96 Lost Volts = 120 - 96 = 24 V Internal resistance = r = ? 24 = ( 1.2+0.4) r r = 15 ohm.
  14. amina1300

    Physics: Post your doubts here!

    op Opps I wrote it the opposite way around -80--x / 4x10^-3 = 60 ,000 We always subtract the smaller potential from the bigger -80 > -320 . My apologies.
  15. amina1300

    Physics: Post your doubts here!

    E = (F/A) /( extension /length) --> Stress : F/A F = W = mg ( g is constant) m = density * volume (density is constant as same material ) V = l * l* l ( The Load is a cube ) [The model is one tenth full-size in all...
  16. amina1300

    Physics: Post your doubts here!

    The Electric Field is upwards hence the Potential of the upper plate should be lower than the lower plate. EFS= V/d 60000= - x - 80/4x10^-3 x= -320 (A)
  17. amina1300

    Physics: Post your doubts here!

    Total distance = 200 km Avg speed = 80 kmh^-1 for 90 km and time taken to travel this distance = 90/80 = 1.125 hrs Total time = 2 hrs Time left = 2- 1.125 = 0.875 hrs Distance left = 200 - 90 = 110 km speed which should be taken = 110/0.875 = 125.7.. = 126kmh-1 (D)
  18. amina1300

    Physics: Post your doubts here!

    I guess you did it like this 8= ;[ 1/R + 1/2R ]^-1 2R/3 = 8 and R = 12 Thankyou the help.
  19. amina1300

    Physics: Post your doubts here!

    http://papers.gceguide.com/A%20Levels/Physics%20(9702)/9702_m16_qp_12.pdf Q37 anyone and 34..35
  20. amina1300

    Physics: Post your doubts here!

    The sphere will not move in a diagonal direction so S= Q For an object submerged in water there will be resultant upthrust force acting on it causing it to move upwards so R>P IT SHOULD FLOAT (e.g place a tennis ball under water it floats.) (B implies that sphere would sink which is not the case)
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