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  1. daredevil

    hahha ohh yay :) yeahh yeah sure... i hope i'm able to answer u (:

    hahha ohh yay :) yeahh yeah sure... i hope i'm able to answer u (:
  2. daredevil

    Chemistry: Post your doubts here!

    someone... ANYONE .... please explain NMR to me!! :``) i seem to not at all be able to do nmr questions :/ :((
  3. daredevil

    no i'm done with AS maths ... and have almost forgotten p1 and totally forgotten p6 :`) :P i'm...

    no i'm done with AS maths ... and have almost forgotten p1 and totally forgotten p6 :`) :P i'm giving p3 and p4 this year :)
  4. daredevil

    Mathematics: Post your doubts here!

    ummm.... wow! u must be a superhero or something. becz i for one know that if i have to reply on this thread with pure dry study stuff i will never be able to actually study. for most people that i know, we are regularly following the threads and between all the studying we do, we actuallly joke...
  5. daredevil

    Best of LUCK!!

    Best of LUCK!!
  6. daredevil

    a levels... freedom's a bit more true for me than u i'm afraid :`)

    a levels... freedom's a bit more true for me than u i'm afraid :`)
  7. daredevil

    huh..... umm well the antidote lies at the end of may for me :') u AS or Alevels ??

    huh..... umm well the antidote lies at the end of may for me :') u AS or Alevels ??
  8. daredevil

    chemistrifying myself!! X__X u?? :P

    chemistrifying myself!! X__X u?? :P
  9. daredevil

    Mathematics: Post your doubts here!

    can u post the paper or the link to the paper?
  10. daredevil

    Mathematics: Post your doubts here!

    from wat i can gather it will be x^2 + 5x - 8 = 0 where a=1 ; b=5, c=-8
  11. daredevil

    Mathematics: Post your doubts here!

    yes it's ryt (Y)
  12. daredevil

    Mathematics: Post your doubts here!

    ummm no .. the answer is x = (sqrt)3a
  13. daredevil

    Mathematics: Post your doubts here!

    I'm sorry i dont get ur question :`) is it a new question or something from the one that i answered??
  14. daredevil

    Mathematics: Post your doubts here!

    bcz u have y as lny in the graph and ur x from the graph is x^2 just rearrange the equation in the form of y=mx+c
  15. daredevil

    Mathematics: Post your doubts here!

    NOTE i am considering @ as thita as u found out in part i .. 4Cos@ + 3Sin@ = 5Cos(@-0.6435) 5Cos(@-0.6435) = 2 Cos(@-0.6435) = 2/5 @ = Cos^-1(2/5) + 0.6435 @= 1.8028 radians and 2(pie)-1.8028 = 4.48 radians can't seem to grasp onto the last part tho :P
  16. daredevil

    Mathematics: Post your doubts here!

    rearrange the equation such that it is in the form: lny = lnA - kx^2 --> lny = -kx^2 + lnA from this u can see that ur gradient will be -k and ur y-intercept is lnA find the gradient using the coordinates of the two given points and equate it to -k .... then put in the values of lny , k, and...
  17. daredevil

    Mathematics: Post your doubts here!

    Praise the Lord...! :') EDIT: May I encounter that same feeling very soon... preferably on 13th May too 0:) :P
  18. daredevil

    Mathematics: Post your doubts here!

    yeah i did get the right answer... it was t=100 what i'm asking is that is t=100 the time when the particle reaches B?? shouldn't 100 be the time when the speed is max??
  19. daredevil

    Mathematics: Post your doubts here!

    ??
  20. daredevil

    Mathematics: Post your doubts here!

    the thing that's confusing me here is that after differentiating we get t=100 ... isn't t=100 the time at which the speed is max? in the ms they have considered it to be the the time taken for the distance AB travelled.... it's confusing me to bits!!:/ and umm well solve the rest of the...
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