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  1. G

    As physics p1 MCQS YEARLY ONLY.

    i dont understand this plz help
  2. G

    Physics: Post your doubts here!

    help plz
  3. G

    Physics: Post your doubts here!

    Bro that was not easy
  4. G

    Physics: Post your doubts here!

    The question asks us about mean power. key word mean. power=i^2*R we only have one value for R so we leave it alone. for current we have 2 distinct values 2A and -1A. so we take the avg value of I^2. SO watch this yea, its so cool. (2^2)+(-1^2)/2=2.5A^2 times that by 100ohms becuase of I^2*R to...
  5. G

    Physics: Post your doubts here!

    question 5. each box is 0.2A. x coordinates and y coordinates are only equal at one point and that is 0.8A question 14 take moments about the end of the truck. (this will just be trial and error) A) cannot because clockwise moment does'nt equal anitclockwise moment. only viable option is B where...
  6. G

    Physics: Post your doubts here!

    lol CIE really tries to throw us under the bus. 2100*25=5.3kw cause its asking about thermal energy so i guess you get that from the drag and friction :X3:
  7. G

    Physics: Post your doubts here!

    lol beat me to it ;)
  8. G

    Physics: Post your doubts here!

    we first need to find the voltage in the external resistance. so using v=ir hence v=5.5v. since the all of the components are parallel to each other they all have an terminal potential difference of 5.5v current going into the junction= output of junction. so the current going into the internal...
  9. G

    Physics: Post your doubts here!

    ans????
  10. G

    Physics: Post your doubts here!

    first find the power produced by the engine itself. so using force*velocity=power hence 30000/25=1200N notice the car maintains 25m/s therefore forces are balanced and there is no net force. we need to calculate the weight down the slope. so 1400*g*sin(2)=479.3.....N the car has to overcome...
  11. G

    Physics: Post your doubts here!

    nvm i got it
  12. G

    Physics: Post your doubts here!

    how do we do this????
  13. G

    Physics: Post your doubts here!

    use the pressure formula= density*g*depth use depth as 20m
  14. G

    Physics: Post your doubts here!

    Momentum before=momentum after Mv+-mv=2mv Hence the velocity after momentum=0m/s Kinetic energy before= 1/2*mv^2+1/2mv^2=mv^2 Kinetic energy after= 1/2*2mv^2 but since velocity after collision is 0 energy is 0j Kinetic energy loss= energy before-energy after= mv^2-0=mv^2
  15. G

    Physics: Post your doubts here!

    ans???
  16. G

    Physics: Post your doubts here!

    lol same i hardy get in the 30's in paper 1. The problem with this paper is that you easily gain marks and easily loose marks. this is because the questions CIE asks are so retarded..... like how am i suppose to know the order of magnitude of the young modulus of copper. Just pray you got above...
  17. G

    Physics: Post your doubts here!

    could you explain this part-----------> R4/(R3 + R4) * V = R2 /( R2 + R1 ) *V
  18. G

    Physics: Post your doubts here!

    i guess you can think of it in terms of rotation. Both answers A and C apply a couple in the same direction (so they'll be pulling themselves apart) which is not true for the AC lol same case for D, the only answer would be B since the top forces cancel out the bottom forces and hence the object...
  19. G

    Physics: Post your doubts here!

    uhhh this question still baffles me..... couldn't explain why its B
  20. G

    Physics: Post your doubts here!

    A bit confused. didn't the question ask 'what will the original kinetic energy become of 4J become'. you calculated the total energy????
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