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m1 help needed asap!

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oh thanx i understood it...did not realise that the other particle was moving downwards...mark scheme is so confusing
 
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What a conincidence.. i am doing the same past paper.. and distance are NOT same.. the sum of both distance is same... which equals to 10.

I dont think derez any way of doing it considering the time same?!?
 
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k there might be....can u share with us?... but keeping distance same is illogical.
 
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Its pretty simple. To things are moving under the principal of constant acceleration. So, we only consider the constant acceleration formula's. Next, we've been given the height as 10 m. So, the sum of the distance that the two particles have travelled during their motion will be 10 m . The only difference is that for one gravitational pull is in the opposite direction.

Form two equations using the appropriate distance formula. Sum them and equate them to 10.
 
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Oh okayy... but still u cant do it by keeping the time same rite?... [nd isnt the signature image too big o_O ??]
 
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I took a pic of this big dice i have at home.. ~(which i also made myself :D) nd then sum inverting of colours and some text... and tada!! a cool sig :)..
 
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ok so can you please explain the graph in june 02 question 7 last part? the mark scheme is confusing me!!!
 
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Okay i hope u have the graph from M.S in front of you here is how it is,

From t=0 sec to t=2 seconds, both particles A and B are accelerating in opposing directions. That is why velocity of B is taken +ve and velocity of A is taken -ve

B stops after 2 seconds

From t= 2 sec to t=2.5 sec, particle A is slowing down due to gravity and stops at t= 2.5 sec (where v=0 and graph cuts x axis). This is the maximum point of A motion.

From t=2.5 sec to t=3 sec, particle A starts to move down again in downward direction and string becomes taut. Here the gradient of graph will be similar to that of motion from lowest to highest point. but it's position is in the positive direction as we have taken all the velocities travelling upwards as +ve.

Hope this helps and feel free to ask any other questions.
 
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thankyou!!! that helped alot!!! ok one more question...in the questions related to energy, what equation should we keep in mind as in loss in g.p.e=gain in k.e + WD against friction etc ....? and do you have any tips and tricks for m1 and specially questions related to energy?
 
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Well im still not confident with my own energy and power concepts. However i have found the use of following helpful,

Always use the law of conservation of energy, which means;

Meachanical energy at start= Mechanical enrgy at end

=> where mechanical energy is the sum of kinetic and potential energies (which maybe loss or gain) and also the work done against other forces.

Just balance out all the energies around the equal to sign from the initial condition in the question at left hand side to the final condition given in the question at right hand side, and find out the uknown. That is what i have tried and is helpful for me. Just try to keep in mind every aspect of the question when making equations and balance it out.
 
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