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Mathematics: Post your doubts here!

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ans q1) a- 06 41 ((( you can simply use cal. to get the time )))
b-204 $ (( ( 850x2.86)-(850x2.62) )))
ans q2) 3000 pounds ((( 1.96x 25000=49000 - 49000/1.75 = 28000 - 28000-25000 = 3000 )))
i hope i helped :) ...... check it if it is wrong plz ....
thanks they are right
 
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http://www.mediafire.com/?440dtidvkdvi282 question 9, totally confused >_< how to solveE ?
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use the formula a+(n-1)d ((( but only with artjematic seq. { adding or subtracting } )))
a= first term
d= common difference
s0 it will be --> 2n-1 then put the root
then for b) (2 x 29)-1 = 57 = root 57
hope i helped :)...check it if it is ok :)
 
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In summer 2011, paper 21, question 18 (a) ii) i get an answer of (-r/2+3q) but the marking scheme says ((-r+3q)/2). Can someone explain how?
 
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May/June 2010 paper 22 Q8???????????????????????? plz plz help
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8-a- will be 45 (( the intersection point between the 2 curves ))) { as i think }
b- will be 62 ((( at x= 62 the sine curve = 0.9 and the cosine curve = 0.4 so the difference at Y= 0.5 )))
check it pllz i'm not sure :)
 
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8-a- will be 45 (( the intersection point between the 2 curves ))) { as i think }
b- will be 62 ((( at x= 62 the sine curve = 0.9 and the cosine curve = 0.4 so the difference at Y= 0.5 )))
check it pllz i'm not sure :)
(a) is right but (b) is 64 nt 62....bases on what???
 
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In summer 2011, paper 21, question 18 (a) ii) i get an answer of (-r/2+3q) but the marking scheme says ((-r+3q)/2). Can someone explain how?
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i think i got it
u can get RS which is (( -r+3q )) then M in the midpoint so it needs only half the distance so divide it all by 2 not only -r
plz tell me if u got it :) hope i helped :)
 
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(a) is right but (b) is 64 nt 62....bases on what???
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i think that the problem is in reading the graph
we can say that every unit = 3 so try to get the number which matches the needed difference in Y
what do u think about it ?? did u got it ??
 
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http://www.xtremepapers.com/papers/...cs (with coursework) (0581)/0581_s09_qp_2.pdf :Question 3 and 11:
May june 2011varent 23:Question 19/17b only and 12
0581_s09_qp_2.pdf
Q3 a) 05 06+01 35=06 41
b) $2.62 will give you 2227(2.62*850)
$2.86 will give you how much? (cross multiply)
=2431
therefore 2431-2227=$204
Q11) $1.96 = £1
? =£25 000
=$49000
$1.75 = £1
$49000=?
=$28000

May june 2011varent 23
Q19) a) 1:250000
? : ( 80*100000)
=32cm
b) (1)^2 ) : (25000)^2
6 : ?
=37.5km
 
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i think that the problem is in reading the graph
we can say that every unit = 3 so try to get the number which matches the needed difference in Y
what do u think about it ?? did u got it ??
i mean how am i supposed to know the difference? like there are many differences what can lead to 0.5..like .7-.2??
 
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i mean how am i supposed to know the difference? like there are many differences what can lead to 0.5..like .7-.2??
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we need only ONE POINT ON X which make a difference of 0.5 in Y
if we suggested .7 and .2 , they will not match on one point on X ...... SO we should find that one point and can't be any other1.....got it???
 
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