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Recent content by Nikesh
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Re-exam doubt!!!!
If we get B in Mathematics n want to appear again in next session to improve grades, n unfortunately if xm is spoiled than before than wat effect will it have to the previous grade??? will it be changed or remains same??? -
CIE May\June examination session ending soon
this year's may\june session has finally ended, hope you are all feeling relief and are all done with exams......ENJOY THE VACATION GUYS -
AS Physics P1 MCQs Preparation Thread.
question says ball is dropped....which means its currently in rest, had it been moving, it could not be dropped i guess what you say??? -
AS Physics P1 MCQs Preparation Thread.
its C --> for first case when the sphere is dropped u^2 = 0 + 2as (let s be total height of the fall) i.e. u = (2as)^1/2.........................(i) -->2nd case for bounce 0 = v^2 - 2a(s/2) (since the height is half of total height this time) or, as = v^2 i.e. v = (as)^1/2 now, v\u = (as/... -
CIE May\June examination session ending soon
After a long routine of about 1 and half months, may\june session of this year is ending in few days. A final exam i.e. Physics P1 is left to be nailed. How are your preparations going on?? And also how did you all do rest of the papers ??? BEST OF LUCK FOR COMING EXAM AND RESULTS TOO...!!!!! -
Mathematics: Post your doubts here!
Use the formula Vaverage = Total distance travelled / total time taken i.e. --> let s1 be distance traveled till t= 50 s -->i.e. s1 = 0.6 * 50^2 - 0.004 * 50^3 (use given equation of displacement which is x = 0.6t^2 - 0.004t^3) = 1000m --> let s2 be distance traveled after t>=50s --> i.e. s2=... -
How was Math P1??????
i too got same answer.. it must be the correct answer -
How was Math P1??????
Don't worry, you will secure a good grade Do good in rest of the exams, and you will touch the apex.. GOOD LUCK (y) -
How was Math P1??????
How did you all do todays Math P1 examination?? Was it really hard, normal or easier paper?? :) -
Mathematics: Post your doubts here!
Q3 compare given equation with ax2 + bx = c = 0, and deduce determinant i.e. (b2-4ac)^1/2 --> since equation has 2 roots, determinant is >0 i.e. (b2-4ac)^1/2 > 0 --> Solve and find values of p and q -
Mathematics: Post your doubts here!
--> 2(ii) (1-3/2x)^6 --> expand it to the term of x^3 --> then multiply expression obtained with(k + 2x) you will two terms with x^3 include term with k equate that with 0, solve it you will get value of k -
BEST OF LUCK (MATH P1 STARTING IN 6 hours)
All students who are appearing math p1 students..... I wish u all best wishes may you solve every problems accurately in minimum time anyone having problems can still share the problem. GOD BLESS -
Mathematics: Post your doubts here!
if question is tan(1/2pi - x ) then it goes like this given tanx = k now tan(1/2pi - x) = tan (90 - x) = cotx = 1/tanx = 1/k...simple -
Mathematics: Post your doubts here!
for 3 (ii) Let AB = (1/k) m (Since they are both parallel) i.e. m = ABk.........(i) use given position vectors to find AB when p=4 and then find vector m in terms of k with above equation....(i) u r then given magnitude of m i.e. |m| = 28 use magnitude formula u will get k=4 now substitute... -
Mathematics: Post your doubts here!
for i) you might have expanded given expression up to 3rd terms ii) first let y = 2x - x^2 and then use your expanded expression in (i) simplify all terms and then you will find coefficient of x^2