one more thing...Lattice energy is just affected by two things: radius size and charge..Because charge for both Mg and Ba is same, so we can only compare radius size
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SadiaMaryam
22shimmer22girly
4d(i) NH3CH2CO2^-1 Na^+1 i drew it out and would sent u a screenshot but net probs suck
22shimmer22girly
4d(ii) Na+ -O-C6H4-CH2CH(NH3)CO2^-1 Na+ i drew it out too
SadiaMaryam
its ok..u should better not send because it'll waste ur time (due to ur network problem). I'll try it anyhow
22shimmer22girly
4d(iii) Cl^-1 +^NH3 (CH3)4 CH(N^4 H3) COOH CL^-1
22shimmer22girly
noo noo its okay i am writing them out for u
SadiaMaryam
alright thank you
22shimmer22girly
4d(iv) CH2 at position 1 -the benzene ring and OH at position 4 and bromine at positions 2 and 6 as they are equal
22shimmer22girly
i hope that helped and thank u for the lattice energy
SadiaMaryam
yeah. it really helped TY
22shimmer22girly
btw i had probs wid 3b(ii) like why do they multiply by 5 and then 4?.....i will look at it again and do u have any others cause i have 2 more
22shimmer22girly
ur welcome honeeey
SadiaMaryam
good question! x5 is to balance the electrons. 1 half eq: MnO4^-2 +8H+ +5e ---->Mn^+2+4H2O
SadiaMaryam
the other half eq: Fe^+2 ---->Fe^+3 +e-
SadiaMaryam
to balance the 5 electrons in eq1, we multiply the second eq. by 5
22shimmer22girly
thank u and times 4?
SadiaMaryam
multiplying by 4 is just like : no. of moles/25 x 100... this is actually finding the no. of moles in 100 dm3 with the respect to the moles in 25dm3
22shimmer22girly
i will look at it and thank u sooo muchhh
22shimmer22girly
thank uuu soo sooo much i get in now
SadiaMaryam
by the way, did u really understand it or not? coz I'm not good at explaining things