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Whats App A level Tutor. Contact me on whats app for details: +919426116018

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y = k - 2x y = x^2 - 6x + 14 Equate them k - 2x = x^2 - 6x + 14 x^2 - 4x + 14 - k = 0 As tangent meet once to the curve we can say that D = b^2 - 4ac = 0 16 - 4(14 - k) = 0 k = 10 P.s. If you wanna join As and A level whats app group, give me a message on my whats app number: +919426116018...

aere you still in contact with Adeena/

Nice name :V Welcome to XPC Family...

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I take onlline classes on hourly basis on whats app and I train people like you to understand the paper style and the content in any chapter they are stuck at. I charge 5 pounds per hour. If you need more details, msg me on my whats app : +919426116018

(n+1)! = (n + 1) * ( n)! therefore the answer to this question is (n + 1)

2x^2 - 2x > 9 2x^2 - 2x - 9 > 0 Solve this. And suppose u got solme value a and b where b < a then ur final answer will be x > a and x < b