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  1. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    i believe the paper was not that hard, if you worked through all past exams , you will find that most of the questions given were asked before. However i do agree that it was a lengthy paper, 11 numbers were too much but 10 would be fine. Anybody else find that the marks allocated were also...
  2. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    i remember getting that for AC lol
  3. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    do you remember what you got for oc? This is probably why everyone is getting different answers, did you get 2i + 5j + 4k for OC?
  4. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    yes yes you didnt state the 0 and 360 limits
  5. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    od = 2i + 4k oa = 4i ob = 5j
  6. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    i remember getting 75 or 76 something
  7. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    do you remember what you got for vector OC ?
  8. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    oh yes im sry...for the trig question it was 7 + 4= 11 and -4 + 7 = 3
  9. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    its probably k > 9 , because if u send b^2 ( b can never be negative )on the RHS, you need to divide by a -ve number to make it become positive, .... ( b^2 - 4ac <0) also i remember getting k = 11 (b^2-4ac =0)
  10. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    feel free to do the volume part lol, im tired , u got all the info necessary, limits 6 and 2 [4 - (x/2 + 6/x )]^2
  11. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    y = 4 y = x/2 + 6 /x 4 = x/2 + 6/x = > x^2 -8x + 12 (x-6)(x-4) = 0 x= 6 or x=4 dydx = 0.5 - 6/x^2 m at x = 6, is 1/3 m at x =2 is -1 point p ( 2,4) point q (6,4) equation of tangent passing through p , y - 4 / x - 2 = -1 => y= -x + 6 equation of tangent passing through q, y -4 / x -6 = 1/3...
  12. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    2y + 3x = k 2y = -3x + k m of perpendicular bisector = -(3/2) m of line AB = -(3/2) x m (ab) = -1 M ab = 2/3 5h -h/ (4h+6) -h = 2/3 4h /3h +6= 2/3 12h =6h +12 h = 2 A = ( 2,2) B ( 12 ,10) Mid of AB = (7 , 6) 2(6) + 3(7) =k k =33
  13. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    they cant be the same... the gradient of one should be the -ve reverse of the other.... and yes their points of intersection meet on the line y=x , which when you equate both, gives you an x that equals to the y
  14. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    anyway h is 2 , h is 1 is not good
  15. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    did you reverse the gradient of the perpendicular bisector>? then use y 2 - y1 / x2 -x1 = to that gradient? this gives h. then use mid point of AB and replace it into the equation of the bisector to get k A = ( h,h) , B = 4(h) +6 , 5h)
  16. B

    AS math 9709/May June/2018/ Paper 12 Hard Or Easy?

    binomial, a = 3 k<9 and k = 11 a = 8000 , r = 1.02 h= 1 k =22 a = 7 b= -4 , for no solution k > 7 , and k < 3 x = 146 , 323 range for which 2cos > -3sin , 0 >x> 146
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