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  1. M.Omar

    <----- And no I am not the one with the close-up :P

    <----- And no I am not the one with the close-up :P
    • M.Omar
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  2. M.Omar

    RECHECK , REMARKING

    well tht is certainly very unexpected! https://drive.google.com/open?id=0B8IFY4QZ6NtbSlY2RGpoWF9VcGs use this link for ur marking schemes..if u r on facebook..then type O/A Level Resources .on that page u,ll find the gts and question papers and mark schemes.... I honestly do not know what to...
  3. M.Omar

    RECHECK , REMARKING

    What were ur grades if u dont mind telling in the other subs and the one sub or subs u want to recheck?I mean if there is a vast disparity between them then it might mean sth else than rechecking ,mismanagement perhaps but that is assuming that the grades were wrong (in ur view) in more than 2...
  4. M.Omar

    RECHECK , REMARKING

    Well my brother,s friend,in the prev year, had his pak std paper rechecked because he felt he did not get a fair grade.I believe he was the only one to have a paper recheck from his batch and he infact did get a grade improvement(B to A).Important thing is definitely that one has to be sure of/...
  5. M.Omar

    Mathematics: Post your doubts here!

    are u sure the question is right ?
  6. M.Omar

    Mathematics: Post your doubts here!

    R=180-(P+Q) cos(R)=cos(180-(P+Q))= - cos( P+Q) (from identity cosx=-cos(180-x)) now simply find -cos(P+Q) by using the formula cos(A+B)=cosAcosB-sinAsinB and sinx=(1-(cosx)^2)^(1/2)
  7. M.Omar

    ~~jokes?? in here?? really??

    an old one.but good in a sick way (for those who get it :P )
  8. M.Omar

    Results: CIE May/June 2016 Examination Series

    Ah still the same old xpc community 2 years back ( dint have any result last year) where the first 8-9 pages of the RESULTS thread would be filled with sorrows,anxieties and with countdowns,most prominently a day before the result.Keep it up! :P
  9. M.Omar

    Results: CIE May/June 2016 Examination Series

    A2
  10. M.Omar

    Results: CIE May/June 2016 Examination Series

    Do you have AS results ?
  11. M.Omar

    we draw a perpendicular bisector through the line joining U and U^2 and then seeing the...

    we draw a perpendicular bisector through the line joining U and U^2 and then seeing the |Z-U^2|< |Z-U| , the < sign means it,s closer to U^2 so we shade the whole region towards U^2 i.e rightwards .the overlapping region we get is a part of a circle (the right segment of the circle) .yeah I...
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  12. M.Omar

    Yes I believe it,s correct . |Z<2| means any complex number with modulus less than 2 so we draw...

    Yes I believe it,s correct . |Z<2| means any complex number with modulus less than 2 so we draw a circle of radius 2,centre the origin, and shade inside . |Z-U^2|< |Z-U| is achieved by first realizing |Z-U^2|=|Z-U| that distance of z(the variable complex number on argand diagram) from both U...
    • M.Omar
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  13. M.Omar

    Mathematics: Post your doubts here!

    I asked a similar question from my teacher as well about a year before I think. He said it,s not a big deal and that both are correct.I do however still opt for drawing a dotted line for < or > sign. You could write as a side note a max of 5 words abt the point of drawing a dotted line in case u...
  14. M.Omar

    Nopes. :P

    Nopes. :P
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  15. M.Omar

    so we see with radius of 1 it would touch line x=0 and thus its min arg would be pi/2 (90...

    so we see with radius of 1 it would touch line x=0 and thus its min arg would be pi/2 (90 degress) ... for max arg we draw a line from origin to other end of diameter so that the total length opposite to origin is 2*radius=1 and length of base =3 to give angle with y axis = tan^-1(2/3) and...
    • M.Omar
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  16. M.Omar

    I believe u wud have a sketch of a shaded semicircle facing upwards.... (its diameter wud be...

    I believe u wud have a sketch of a shaded semicircle facing upwards.... (its diameter wud be line y=3 (Imaginary line =3) and with radius 1 ..it,s centre wud be (-1,3)
    • M.Omar
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  17. M.Omar

    greatest arg is indeed 2.16(3sf) which approx equal to 2.2 as she stated

    greatest arg is indeed 2.16(3sf) which approx equal to 2.2 as she stated
    • M.Omar
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  18. M.Omar

    i am getting arctan(2/3) as answer... greatest val in my view req some calculations ...great4est...

    i am getting arctan(2/3) as answer... greatest val in my view req some calculations ...great4est arg is arctan(2/3) +pi/2 and smallest arg by observation of the sketch is pi/2 to give difference =arctan(2/3)
    • M.Omar
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  19. M.Omar

    sure.did F maths course in tht so i guess

    sure.did F maths course in tht so i guess
    • M.Omar
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  20. M.Omar

    a trite clichéd remark, with tautology being employed for emphasis

    a trite clichéd remark, with tautology being employed for emphasis
    • M.Omar
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