Can anyone solve this? (Chem ATP Question)

[Shadow_Beast]

Can anyone solve this question. Its fairly easy but i cant seem to solve it. Its from the Chemistry ATP Paper 41 of June 2011

 

[SalmanPakRocks]

That's easy. Just calculate it by this method:
Mr of Nitrogen/Mr of total compound * 1000

 

[Shadow_Beast]

That's easy. Just calculate it by this method:
Mr of Nitrogen/Mr of total compound * 1000

That's easy. Just calculate it by this method:
Mr of Nitrogen/Mr of total compound * 1000

That cant be it coz its ATP and they give you the Ar for questions invoolving calculation of Mr. This question's from the Titration question.

 

[Ikram Khaliq]

View attachment 10342 Can anyone solve this question. Its fairly easy but i cant seem to solve it. Its from the Chemistry ATP Paper 41 of June 2011

Use ratio. If the original mass( calculated in the first part) produces x grams of ammonia, how much will 1000 grams of F produce?

 

[haha101]

see look !

1.76 ( from part a) ------------------> 0.319(previous part)
1000(from Q)-----------------------> x

x=222.16 !

I know dat marking scheme mei ans is diff but my sig figs are wrong ! =)
hope it helped

 

[asd]

View attachment 10342 Can anyone solve this question. Its fairly easy but i cant seem to solve it. Its from the Chemistry ATP Paper 41 of June 2011

You know the answer to part (i) ? It's 0.3876 ... u got it?
Now, they ask for 1000 g of ammonia. o.3876 g of ammonia was produced from the sample they had used. The sample was of 1.76g.
For each gram of F the mass of ammonia produced will therefore be = 0.3876/1.76 =0.2202g
For 1000g, multiply this by 1000. You will get 220.2g
Phew, Now this must be helping (I hope)

 

[Shadow_Beast]

Oh awesome thanks guys

 

[khalil]

The haha guy is right , for such a question you have to do a comparision .
The original mass (1.57 i think ) got you this mass of ammonia (XYZ)
then (1000g) will get you (Xg) of ammonia .

hence 1.57X = 1000 (xyz)
X = 1000xyz/1.57