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chemistry paper 22

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IF it is variant 2.. then the answer is Pentan-2-ol !! this is because when u r remvong H2) u can remove it from either side of the OH !
 
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If it is variant 1.. then J would react with ITESELF to form a cyclic compund... How this happnes :

COnsider that 2 moles of J are present... then the OH from 1st would react with COOH from 2nd and the COOH from the 1st would react with the OH of the second.. Esterification at both ends occur and this monstrous compound is formed :p
 
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ashhadazam said:
If it is variant 1.. then J would react with ITESELF to form a cyclic compund... How this happnes :

COnsider that 2 moles of J are present... then the OH from 1st would react with COOH from 2nd and the COOH from the 1st would react with the OH of the second.. Esterification at both ends occur and this monstrous compound is formed :p



IS DIS 4RM A2?????? :evil: :evil: :evil:
 
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hahaha.. no its obviously no frm A2.. Its an esterification reaction but a tricky one.. the compund itself has two groups necessary to make an ester.. !!! and H2SO4 catalyses the eserification process. !!!
 
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does variant paper 1 and variant paper 2
or
paper21 and paper22 take place at the same day or is it different if yes...can anyone please post what came out in paper 21
 
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okay i repeat try reading electrolysis
SN1 and SN2 substitiution
bonding and structure
confusing organic
dont forget Kp equilibrium
 
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