help...maths question

[hassam]

f(x)=(x+1)(x+2) .....domain is all +ve real no......
find the range of function?

see attachment for the curve of function

 

[soumayya]

since the domain is x > 0 , we find the values of y when x > 0
When x=0, y=2
Thus, as seen from the graph, the values of y are greater than 2
Therefore, range: y > 2