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Mathematics Paper 1 :)

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ME! Im not worried at all! we get like 3 1/2 days to study for it
 
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my real reason for being worried is only
TRANSFORMATIONS and PROBABILITY....
if anyone can help me anyhow ????????
 

XPFMember

XPRS Moderator
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u may find some useful tips and other stuff here in some of my posts :) Let me know if u need more :)
 
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d0nt forget to revise statistics (mean,mode,median), probability,circles,similar triangles...these questions are recurring!!!
 
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The diagrams shows the triangle PQR.
The points S and T lie on the lines PQ and PR respectively.
The line ST is parallel to the line QR.



[a] Angle QST = 116 and angle QRT = 49.
Find angle QPR.

U and V are points on ST and QR respectively.
PUV is a straight line with 2PU = UV and angle PVR = 90.

Find
PU : PV
[ii] the ratio of the area of the trapezium STRQ to the area of the triangle PQR.(problem on this one)
 

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Depletion said:
The diagrams shows the triangle PQR.
The points S and T lie on the lines PQ and PR respectively.
The line ST is parallel to the line QR.



[a] Angle QST = 116 and angle QRT = 49.
Find angle QPR.

U and V are points on ST and QR respectively.
PUV is a straight line with 2PU = UV and angle PVR = 90.

Find
PU : PV
[ii] the ratio of the area of the trapezium STRQ to the area of the triangle PQR.(problem on this one)



wait i guess i know this..
i'll go and search it..
 
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Diishiik Douw said:
Can You help me with this question?
(without calculator)

(4.302 x 29.88)^2÷ √150

There should be given more details...please see the question again!!!
 
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Depletion said:
Diishiik Douw said:
Can You help me with this question?
(without calculator)

(4.302 x 29.88)^2÷ √150

There should be given more details...please see the question again!!!


No the questiOn says:
Estimate the value ,correct to one significant figure, of (4.302 x 29.88)^2÷ √150

that's all

it's from October/novemver paper 1 number 19 (a) :(
 
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mayB i know..since its asking to one sig fig...
u shoud round off those num to 1 sig fig also..
(4 x 30 )^2 and (√150) is approximate to 12 since 12*12 =144 and 13*13 =169 so, √150 should lies in between...
(120)^2 / 12
14400/12 = 1200
 
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Depletion said:
The diagrams shows the triangle PQR.
The points S and T lie on the lines PQ and PR respectively.
The line ST is parallel to the line QR.



[a] Angle QST = 116 and angle QRT = 49.
Find angle QPR.

U and V are points on ST and QR respectively.
PUV is a straight line with 2PU = UV and angle PVR = 90.

Find
PU : PV
[ii] the ratio of the area of the trapezium STRQ to the area of the triangle PQR.(problem on this one)
 
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Depletion said:
The diagrams shows the triangle PQR.
The points S and T lie on the lines PQ and PR respectively.
The line ST is parallel to the line QR.



[a] Angle QST = 116 and angle QRT = 49.
Find angle QPR.

U and V are points on ST and QR respectively.
PUV is a straight line with 2PU = UV and angle PVR = 90.

Find
PU : PV
[ii] the ratio of the area of the trapezium STRQ to the area of the triangle PQR.(problem on this one)

heyyyy i have the answer but in the form of an image on paint..
 
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