Paper 4 miscelleanous(bio+che+phy)

[hassam]

i ll be posting questions in this thread.....u ppl can anser and we cn discuss ...... this is one of the concept-maker question on Ksp

 

[hassam]

question on transition metal

 

[ad98ify]

can anyone answer this?

 

[hassam]

brother anser....m i ryt???
plus u try that Ksp question...its really good to test ur concept

 

[hassam]

brother plx tell the graph for this.....will lenz law be foolllowed here.......if no then WHY not???

 

[XPFMember]

brother plx tell the graph for this.....will lenz law be foolllowed here.......if no then WHY not???

Assalamoalaikum wr wb!
I just did this question...
ummm I used Faraday's law...phi is proportional to B
and E is proportional to rate of flux linkage do/dt
so E will be the gradient of the graph above...that's what i did..i dunno if it's wrong ....

 

[hassam]

yea thats fine.....bt there's a cnfusion in my mind that why we r nt using e=-d(phi)/dt

 

[XPFMember]

yea thats fine.....bt there's a cnfusion in my mind that why we r nt using e=-d(phi)/dt

may be we have to do that..i did it wrong..
ms just mentions they are in opposite directions and correct positions...
umm i guess u r right..

 

[ad98ify]

brother anser....m i ryt???
plus u try that Ksp question...its really good to test ur concept

following is the answer. and i think u r correct. can u explain me how did you come up with the structure please?
will surely solve your question soon.

 

[ad98ify]

yea thats fine.....bt there's a cnfusion in my mind that why we r nt using e=-d(phi)/dt

E= Nd phi/ dT
phi is directly proportional to B like xpf memeber rightly quoted.
b is directly proportional to current I as seen in the formula:-
B=uI/2 pie a
hence the gradient of I/T graph would give Emf. but in the negative axis as you dont have to forget the minus sign there!