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Please help me understand These kind of questions :/
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Physics -__
- Thread starter Atif Aziz
- Start date
As the temperature increases, the resistance of the thermistor will decrease, so the overall resistance of the 5000 ohm resister in parallel with the thermistor will decrease according to 1/Rt=1/R1+1/R2
so accordingly, the voltage through it decreases too (V=RI)
and the voltage through the 2000 ohm resister will increase (Vt=V1+V2)
so the reading in the voltmeter will increase as the temperature will decrease.
V1=3.6V therefore................................V2=6-3.6=2.4V
R1=2000...............................................R2=5000x/5000+x......(where x is the resistance of the thermistor)
I1=V1/R1
I1=5000/3.6=555.55A therefore......... I2=555.5( I1=I2)
now u can use the formula R=V/I to calculate the value of x
I hope this is right
so accordingly, the voltage through it decreases too (V=RI)
and the voltage through the 2000 ohm resister will increase (Vt=V1+V2)
so the reading in the voltmeter will increase as the temperature will decrease.
V1=3.6V therefore................................V2=6-3.6=2.4V
R1=2000...............................................R2=5000x/5000+x......(where x is the resistance of the thermistor)
I1=V1/R1
I1=5000/3.6=555.55A therefore......... I2=555.5( I1=I2)
now u can use the formula R=V/I to calculate the value of x
I hope this is right
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ANYONE PAPER 6 NOTES (PHYSICS)