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PLease explain Q5 part c in this paper: http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_42.pdf
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physics p4 help
- Thread starter bravegirl123
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That is one difficult question
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Although Value of Current (rms)is given you will find the peak currents that would be (2)^1/2 x 5.6 = 7.92....Max and minimum current woud be this.. By using the force formula you will find
force= 6.57x10-2x6.4x10-2x7.92/9.81= 3.39x10-3 kg... you will get 3.39 g on weighting machine... As current would be reversed force would be 3.39 upwards and downwards.. So variation would be 3.39g+3.39g= 6.78 grams...
force= 6.57x10-2x6.4x10-2x7.92/9.81= 3.39x10-3 kg... you will get 3.39 g on weighting machine... As current would be reversed force would be 3.39 upwards and downwards.. So variation would be 3.39g+3.39g= 6.78 grams...