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Re: A-Level Organic Chemistry Jayanthan
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Re: A-Level Organic Chemistry Notes By Jayanthan
Hey he's my teacher too! He's a great teacher really and his notes are famous throughout Karachi believe me.
Hey he's my teacher too! He's a great teacher really and his notes are famous throughout Karachi believe me.
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Re: A-Level Organic Chemistry Notes By Jayanthan
ull have to sign up first!msk said:
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Re: A-Level Organic Chemistry Notes By Jayanthan
Hey these are just AS, Dont you guys have A2 as well? If you do PLS post them!
Hey these are just AS, Dont you guys have A2 as well? If you do PLS post them!
Re: A-Level Organic Chemistry Notes By Jayanthan
FOR Chemistry PAPER 33!!!!!!!!!!
hydrated ammonim salt titrated with KMnO4
usual salt analysis
one thermal question
We have to titrate ammonium nitrate with KMn04 or would we need to oxidize potassium iodide in the presence of ammonium nitrate and then titrate the resulting solution with sodium thiosulphate? :|
see question no.1 in june2008-31
a similar question is expected!
FOR PHYSICS ASLEVEL PAPER 33
what we hav been practicing is the electricity one with beads in place of resistors.its very simple..and ya in the oscillation one we will be having a cylinder instead of a pendulam bob..
i doubt anything concerning magnets or diodes on A2 level will come for As practicals, hmm, they might just be giving diode as just another component of the circuit system, in past years there were things like that, but the procedure is still the same, you will just have to either measure current, volt etc. and draw the graph, and by the way it will be helpful to review the graphs for diodes. before going for exam.
YOU WILL NEED
1.retort stand.
2.bob/cylinder
3.stopwatch.
4.thread
5.multimeters
6.batteries
7.clamps.
8.resistors.
9.contacts
FOR Chemistry PAPER 33!!!!!!!!!!
hydrated ammonim salt titrated with KMnO4
usual salt analysis
one thermal question
We have to titrate ammonium nitrate with KMn04 or would we need to oxidize potassium iodide in the presence of ammonium nitrate and then titrate the resulting solution with sodium thiosulphate? :|
see question no.1 in june2008-31
a similar question is expected!
FOR PHYSICS ASLEVEL PAPER 33
what we hav been practicing is the electricity one with beads in place of resistors.its very simple..and ya in the oscillation one we will be having a cylinder instead of a pendulam bob..
i doubt anything concerning magnets or diodes on A2 level will come for As practicals, hmm, they might just be giving diode as just another component of the circuit system, in past years there were things like that, but the procedure is still the same, you will just have to either measure current, volt etc. and draw the graph, and by the way it will be helpful to review the graphs for diodes. before going for exam.
YOU WILL NEED
1.retort stand.
2.bob/cylinder
3.stopwatch.
4.thread
5.multimeters
6.batteries
7.clamps.
8.resistors.
9.contacts
- Messages
- 380
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- 28
Re: A-Level Organic Chemistry Notes By Jayanthan
http://notezone.net/cambridgechem/chemi ... sis%5D.pdf can sum1 go in dix page 11 n do solve n gimme answers plzzzz i cant able to slove it n it might cum for exam help mee!!!!
http://notezone.net/cambridgechem/chemi ... sis%5D.pdf can sum1 go in dix page 11 n do solve n gimme answers plzzzz i cant able to slove it n it might cum for exam help mee!!!!
Re: A-Level Organic Chemistry Notes By Jayanthan
below answers
First of all you need the mass of FA1. In the first table you have the mass of the empty test tube and the mass of the test tube + FA1. All you do is subtract the values 12.80 - 10.50 giving you 2.30g of FA1.
In the second table you need the mass of FA1 after heating. Again, you just subtract the values 11.76 - 10.50 = 1.26g FA1 after heating.
1 d. (i) The mass of anhydrous XS04 present in the crystals is what is left over after heating = 1.26g
1 d. (ii) The mass of water driven from the crystals is the loss in mass that has occurred when the FA1 was heated. Before heating there were 2.30g of FA1 and after heating there were 1.26g. So the mass of water lost is 2.30 - 1.26 = 1.04g
1 e. To calculate the number of moles of water in the sample of FA1 you use the formula no. of moles = mass/mass of 1 mole which gives you 1.04/18 = 0.058 mol
1 f. The number of moles in XSO4
7 moles of H20 gives 1 mole XSO4 (from the formula XSO4.7H20)
So 0.058 moles of water give 0.058/7 = 8.29 x 10 ^ -3 moles of XSO4
1 g. To calculate the relative formula mass of XSO4 you use the formula mass of 1 mole = mass/no. of moles which gives you 1.26/8.29 x 10 ^ -3 = 152.7
1 h. To calculate the Ar of element X you first find the Mr of SO4 which is 32 + (4 x 16) = 96
You subtract this from the RFM from part g giving you 152.7 - 96 = 56.7
below answers
First of all you need the mass of FA1. In the first table you have the mass of the empty test tube and the mass of the test tube + FA1. All you do is subtract the values 12.80 - 10.50 giving you 2.30g of FA1.
In the second table you need the mass of FA1 after heating. Again, you just subtract the values 11.76 - 10.50 = 1.26g FA1 after heating.
1 d. (i) The mass of anhydrous XS04 present in the crystals is what is left over after heating = 1.26g
1 d. (ii) The mass of water driven from the crystals is the loss in mass that has occurred when the FA1 was heated. Before heating there were 2.30g of FA1 and after heating there were 1.26g. So the mass of water lost is 2.30 - 1.26 = 1.04g
1 e. To calculate the number of moles of water in the sample of FA1 you use the formula no. of moles = mass/mass of 1 mole which gives you 1.04/18 = 0.058 mol
1 f. The number of moles in XSO4
7 moles of H20 gives 1 mole XSO4 (from the formula XSO4.7H20)
So 0.058 moles of water give 0.058/7 = 8.29 x 10 ^ -3 moles of XSO4
1 g. To calculate the relative formula mass of XSO4 you use the formula mass of 1 mole = mass/no. of moles which gives you 1.26/8.29 x 10 ^ -3 = 152.7
1 h. To calculate the Ar of element X you first find the Mr of SO4 which is 32 + (4 x 16) = 96
You subtract this from the RFM from part g giving you 152.7 - 96 = 56.7