sequency 1111

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Here:
 

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b) 6(3)^(r-1) = 2x3(3)^(r-1)=2x3^(r-1+1)=2x3^r

f) 2(2)^(r-1)=2^(r-1+1)=2^r
 
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oooooh ok i got it thanks really but i think even we can write them in the forum you posted earlier and check the pm i have posted have a querry
 
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