Mathematics: Post your doubts here!

[rz123]

Thank You Sooooooooooooooooooooooooooooooooooooooooooo...u r unique u know n U love maths

 

[unique840]

Thank You Sooooooooooooooooooooooooooooooooooooooooooo...u r unique u know n U love maths

ur welcummmm han i really love maths

 

[yuliana95]

Anyone please help me.. I need the answers, urgent... Thanks in advance..

If p(x)=x^5-3x^4+2x^3-2x^2+x+1 , fine the real roots for p(x).
The answer is : 1, 1+square root of 2 and 1- square root of 2.

 

[hassam]

http://www.xtremepapers.com/CIE/Interna ... _qp_31.pdf
q10. part (i) help me out

 

[Silent Hunter]

need explanation of 4(ii) and (iii) on the following paper:

http://www.xtremepapers.com/CIE/Interna ... _qp_62.pdf

need explanation of 4(ii) on the following paper:

http://www.xtremepapers.com/CIE/Interna ... _qp_63.pdf

thank you

 

[Silent Hunter]

anybody???

 

[Muhammad Talha]

Plz solve q:11 of thz paper :
http://www.xtremepapers.com/CIE/Interna ... _qp_12.pdf

 

[abcde]

Plz solve q:11 of thz paper :
http://www.xtremepapers.com/CIE/Interna ... _qp_12.pdf

AoA!
The solved question can be accessed via the mark scheme. What part are you having trouble in?

 

[Muhammad Talha]

Plz solve q:11 of thz paper :
http://www.xtremepapers.com/CIE/Interna ... _qp_12.pdf

AoA!
The solved question can be accessed via the mark scheme. What part are you having trouble in?

Ws.!!
Actually I am having trouble in part 3 n 4?

 

[abcde]

(iii) f(x) = k
=> 4 - 3 sin x = k
=> sin x = (4 - k)/3
sin x has values ranging from 1 to -1.
=> -1 ≤ (4 - k)/3 ≤ 1
=> k ≤ 7, k ≥ 1.
So for the function to have no solution, the ranges of k are: k > 7 and k < 1.

(iv)For g to have an inverse, it must be a one-to-one function (any horizontal line through the graph should intersect it at most once.From the sketch below, you can see that the greatest value would be 3 pi/2. If this value is exceeded, a horizontal line can cut the graph of g twice!

 

[Silent Hunter]

anybody taking statistics????????

 

[XPFMember]

Assalamoalaikum!!

Yeah I take!

Cud you plz say exactly where are you stuck? Did you see the mark scheme...?? I felt it wasn't difficult dont worry....tell me what's ur confusion!? Ok?

 

[Silent Hunter]

http://www.xtremepapers.com/CIE/Interna ... _qp_62.pdf

I HAVE confusion in this paper 4 (iii)

why not 9C4 as they have asked for 4 selections out of 9? they have taken 5C3 in MS

 

[XPFMember]

Assalamoalaikum!!

Remember, for such questions, when you are definitely to chose something, etc. dont consider that when making selections etc..
So in this case there are 2 possible combinations: either one S or 2 S

SO with one S...you have to choose 3 other letters...remember not to count P...neither shud u count S...so only 5 letters...5C3

similarly if there are 2 S then 2 other letters...5C2

total= 5C3 + 5C2 = 20

hope that's clear now!

 

[Silent Hunter]

got it..... thanks alot

 

[ninjas4life]

can someone tell me how to do this quick..?!!

 

[abcde]

AoA!
Perimeter of sector AMN = 1/2 perimeter of rectangle
=> 2r + rx = 4a
=> a = r (2 + x)/4
Now, sin x = BC/AN = a/r
Substituting a into this equation gives sin x = (2 + x)/4.

 

[ninjas4life]

where does 2r come from?..sry..

 

[abcde]

where does 2r come from?..sry..

Sector AMN consists of two radii and an arc. Hence, its perimeter is ( 2r + rx). Feel free to ask anything that boggles your mind.

 

[Silent Hunter]

how sinx = BC/AN ??