AFTER 24 hr .. P1 discussion here !

[Numnum]

thats cause i and a friend went and discussed our answers i got this whole question iguess wrong and i forgot one value of K rest was ok . well u can have an estimation

Lol cool. What do you think the GT will be? Above 60?

 

[Beaconite007]

thats cause i and a friend went and discussed our answers i got this whole question iguess wrong and i forgot one value of K rest was ok . well u can have an estimation

Same as me. Missed out on one value of k.
And got 1 question wrong.
But the one I got wrong was the one that mattered the most :/
Question 7... *sigh*

 

[A star]

Lol cool. What do you think the GT will be? Above 60?

ofcouse 63 or 62 in my opinion i hope so or itll be a B

 

[AdeelRox]

if that is right then if it wasnt for the Q7 i would have achieved 72 darn it :/

my expectation was 74 because of that function mistake, now i have spotted 2 mark further mistake, in the perimeter of the circular measure.
disappointment ;(

 

[muhammadrafay]

What was the Domain and range in function question ? I got
Y ≥ 1
-2.5 ≤ X and less than zero

 

[istudent]

whtz the answer for 10 (b)

1.166

 

[istudent]

hey guys I cotinued my question on extra sheet does it cause any problem ....I mean i did half of question on answer sheet provided and half on extra sheet
please tell me

 

[Numnum]

my expectation was 74 because of that function mistake, now i have spotted 2 mark further mistake, in the perimeter of the circular measure.
disappointment ;(

What'd you do wrong in the perimeter?

 

[Numnum]

hey guys I cotinued my question on extra sheet does it cause any problem ....I mean i did half of question on answer sheet provided and half on extra sheet
please tell me

Me too did you write continuation?

 

[AdeelRox]

What'd you do wrong in the perimeter?

it was an extremely foolish mistake, though we were given the square i forgot the fact and went on to calculate the lenght of BC by using cosine rule but I didnt used the correct formula. Instead of using a^2= b^2 + c^2 -2bccosA i used a^2= b^2 + c^2 -bccosA
I forgot the 2 in the formula and got the lenght of BC as 11.36 instead of the original lenght which was 10. hence my perimeter got incorrect

 

[Numnum]

it was an extremely foolish mistake, though we were given the square i forgot the fact and went on to calculate the lenght of BC by using cosine rule but I didnt used the correct formula. Instead of using a^2= b^2 + c^2 -2bccosA i used a^2= b^2 + c^2 -bccosA
I forgot the 2 in the formula and got the lenght of BC as 11.36 instead of the original lenght which was 10. hence my perimeter got incorrect

Ow well things happen for a reason so ^.^

 

[yousef]

The question gives point R (-1.3) and line of 3y + 2x = 33 as the mirror. We are looking for the image of R, (let's name it as P)

Rearranging the equation of the mirror gives us y = -2x/3 + 11

Therefore gradient (m) of mirror is -2/3.

Since we understand that the line PR will be PERPENDICULAR to mirror (properties of reflection), therefore m of PR = 1.5.

Work out the equation of PR from the point (-1,3) and m of 1.5

y - 3 = 1.5 (x+1)

y = 1.5 x + 4.5

Another properties of mirror is that distance from object to mirror = distance from image to mirror. Therefore point of intersection of line PR and the mirror will be the MIDPOINT for line PR.

Working out simultaneous equation on PR and mirror,

y = 1.5 x + 4.5
y = -2x/3 + 11

1.5 x + 4.5 = -2x/3 + 11

9x + 27 = -4x + 66

13x = 39
x = 3

Subs x = 3 to any of the 2 equation above, we will get y = 9

Since we know R, and the midpoint, we can work out P.

(-1 + x)/2 = 3 for the x-coordinate and (3+y)/2 = 9 for the y-coordinate

Therefore x = 7 and y = 15

tanks bro ... but wy did tey give us this new concept""
and mashallah how did u attempt to do it... or was it a help from ur teacer

 

[mania _ manal]

Any idea about the gt ??

 

[istudent]

Me too did you write continuation?

Nope!!!!

 

[ahmed abdulla]

hope the gt goes down inshallah ... just pray

 

[Beaconite007]

hope the gt goes down inshallah ... just pray

In Sha Allah.
EVERYBODY!
Say In Sha Allah.