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It was sn1 I can't remember where the carbocation was![]()
why sn1?
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It was sn1 I can't remember where the carbocation was![]()
Because it was a tertiary halogenoalkane, so the surrounding methyl groups stabilise itwhy sn1?
Because it was a tertiary halogenoalkane, so the surrounding methyl groups stabilise it![]()
The question was out of 2 marks right? The marks tend to be for the curly arrows, but I guess you'll lose one for using the SN2 mechanism thoughso will i get a mark ? as final product is same i guess
The question was out of 2 marks right? The marks tend to be for the curly arrows, but I guess you'll lose one for using the SN2 mechanism though
How was the rest of it?
Guys i drew the mechanisms with pencil is it ok??????
U sure? Big stress relief if yes!!!it's ok
U sure? Big stress relief if yes!!!![]()
I made sure that it is clear and dark so hope its okif it doesnt show, they are gonna ask for the actual paper
sn2 is for 1 degree haloalkane and sn1 is for 3 degree haloalkane,,,but the question was 2-chlorobutane so CH3CHClCH2CH3 so 2 degree ,,,,now for 2 degree if it is c-cl bond then sn2 if c-i c-br then sn1 so chill out guys its sn2
guys it said suggest the mechanism, calm down!haha, no.
for secondary halogenoalkanes, they will react by sn1 AND sn2. Although, sn1 is the dominant mechanism.
I think they should accept both![]()
what did u guys put for the MCQ that was like why is sodium chloride more soluble in water than hexane?
also..
why do you acidify to prevent hydrolysis?
and on that question what was the colour change?
thanks![]()
the energy released during hydration is greater than the lattice enthalpy
I checked the equation and it was like
Br2 + H2O <==> 2H^+ + BrO^- + Br^-
So, if you add the acid, you increase the concentration of the Hydrogen ions, so according the Le chatelier's principle, the equilibrium will shift to the left producing Br2, thus opposing the change
emm.. from pale yellow to colorless for the titration (i think)
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