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hi, for this question the answer they say is B!
my question is why not D?
my question is why not D?
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PHYSICS UNIT 4 (6PH04) HELP!
- Thread starter maths maldives
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hi, for this question the answer they say is B!
my question is why not D?
hey nice question.
the answer is D. it cannot be B, then it shud be there mistake..
A uniform field is a region which exerts a force of equal magnitude in that region. an electric field acting in all directions will weaken due to the
equipotentials. and an electric field acting in all directions means its a field produced by a charged particle.
i guess dats da reason.
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whooops!.......
i checked a wrong marking scheme! :-(
the answer is actually D!
im really sorry!.....
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Hey, I'm looking for the Unit 4 January 2013 mark scheme. Could you give me the link ? Please? :c
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here you go!
bangladesh.exams.britishcouncil.org/download_file.php?filename=dhaka/upload/6PH04_01_rms_201303071366015000.pdf
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here you go!
bangladesh.exams.britishcouncil.org/download_file.php?filename=dhaka/upload/6PH04_01_rms_201303071366015000.pdf
Than you so much. =']
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can some one help me with this question?
its from jan 2010 Unit 4!
6- An electron gun uses a potential difference to accelerate electrons from rest to a speed of 2.00*10^7. The potential difference is:
A- 569 V
B- 1140 V
C- 2280 V
D- 4560 V
how to do this?
its from jan 2010 Unit 4!
6- An electron gun uses a potential difference to accelerate electrons from rest to a speed of 2.00*10^7. The potential difference is:
A- 569 V
B- 1140 V
C- 2280 V
D- 4560 V
how to do this?
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kinetic energy(1/2mv^2) =work done(eV) u know the mass of electron and also the velocity which is given in the question...and e=1.60*10^-19 hence u can find potential difference(V)
i hope i am right!! the answer is:B(1140 which is similar to the exact answer 1138.6)- Messages
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sorry for my dumbness! :'(kinetic energy(1/2mv^2) =work done(eV) u know the mass of electron and also the velocity which is given in the question...and e=1.60*10^-19 hence u can find potential difference(V)
still i can't figure out how to do this!
got confused in the eV part!
can you post the full calculations please?
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KE =1/2 mv^2 i.e 1/2 x 9.11x10^-31 x2e7^2 = 1.8x10^-16
KE = eV
Therefore, 1.8E-16/ 1.6E-19 = 1138.75
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thank you very much!
ive got it now!
to convert from eV to V, we have to divide it by 1 Electronvolt, right?
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Listen.eV is charge of electron into the voltage.therefore voltage is KE/charge on electron i.e 1.6x10^-19thank you very much!
ive got it now!
to convert from eV to V, we have to divide it by 1 Electronvolt, right?
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i think the answer is B!
first of all, use W=FS!
then substitute F with F=EQ, which is derived from E=F/Q!
now you have W=EQS!
then substitute E with E=V/d!
now the equation is "W=(V/d)*Q*S"
now,
V is as it is
d is also as it is,
Q is q,
S is x!
now the final answer is (V/d)*q*x
so, what is the answer given in the marking scheme?