Mathematics: Post your doubts here!

[Thought blocker]

12 N in the opposite direction, forming an gle of 30 degrees with the positive x axis....what was the original question that you guys were discussing?

How 12 and 30 ?

 

[kitkat <3 :P]

Oh sorry what question? I kinda skipped over most of these comments cause I didn't have the time

Q7

 

[Snowysangel]

Guys..how the hell do we solve this question

9709/41/ON/10
q3??
i cant e ven resolve the forces
pm me if u can!!

Apply lamis rule

 

[Snowysangel]

How 12 and 30 ?

The three forces are initially inequilibrium ie the resultant is zero. If u remove one of the forces the resultant will then be of the same magnitude as the removed force but in the exact opposite direction

 

[Snowysangel]

Q7

What year?

 

[kitkat <3 :P]

Apply lamis rule

how are we going to find the angles

 

[kitkat <3 :P]

What year?

s2011 41

 

[Snowysangel]

how are we going to find the angles

You have a triangle p1XB...you can calculate P1X cause its the tentionib that string and XB is the tention in that respective string...so appy the cos rule...sorry I don't have the question in front of me so I might be confusing the labels. Anyway you can calculate the third angle by subtracting the calculated one frpm 90

 

[princeali97]

How 12 and 30 ?

because that is the force which is bringing equilibrium to the system.If it is released or removed the resultant will be completely opposite in direction which is 30 degrees clockwise from +ve x-axis.

 

[kitkat <3 :P]

You have a triangle p1XB...you can calculate P1X cause its the tentionib that string and XB is the tention in that respective string...so appy the cos rule...sorry I don't have the question in front of me so I might be confusing the labels. Anyway you can calculate the third angle by subtracting the calculated one frpm 90

thanks

 

[kitkat <3 :P]

You have a triangle p1XB...you can calculate P1X cause its the tentionib that string and XB is the tention in that respective string...so appy the cos rule...sorry I don't have the question in front of me so I might be confusing the labels. Anyway you can calculate the third angle by subtracting the calculated one frpm 90

is XB equal to the weight of B?

 

[Arham93]

thanks

you understood what she explained??.:/..
Can u explain the workings??
PM me!!

 

[Thought blocker]

you understood what she explained??.:/..
Can u explain the workings??
PM me!!

Meko bhi samjhado ji :/

 

[kitkat <3 :P]

you understood what she explained??.:/..
Can u explain the workings??
PM me!!

look XB is equal to weight of B and we have 90 angle too

You have a triangle p1XB...you can calculate P1X cause its the tentionib that string and XB is the tention in that respective string...so appy the cos rule...sorry I don't have the question in front of me so I might be confusing the labels. Anyway you can calculate the third angle by subtracting the calculated one frpm 90

snowy angle i tried it but i still cant solve m sorry can u please eleaborate

 

[princeali97]

W 12 Qp 41 q1.....

 

[Snowysangel]

is XB equal to the weight of B?

Yeah. And p1X is the weight of A

 

[Snowysangel]

If the distance is given in cm...do we convert it into meters? Are the equations only applicable when the quantities are in their SI units?

 

[Thought blocker]

If the distance is given in cm...do we convert it into meters? Are the equations only applicable when the quantities are in their SI units?

I do keep SI units in my P1 Idk about P4 :/

 

[kitkat <3 :P]

If the distance is given in cm...do we convert it into meters? Are the equations only applicable when the quantities are in their SI units?

i think it is necessary to change em

 

[Arham93]

i understamd that much that we have to apply Lamis theorem
Now i understand that 7.3/sin(90)=5.5/sin(X)...how do we find X??
marking scheme says 7.3/sin(90)=5.5/sin(90+a)...
why??...:X