PHYSICS p42 GT

[TANJIAHOU]

using s=r(theta) would give circular length. we had to find its diaameter, right?

Diameter was given if i'm not mistaken lol.

 

[Fatima Iftikhar]

Diameter was given if i'm not mistaken lol.

it wasnt given. :O
we had to find the minimum diameter of a crater, that could be seen using that telescope.

 

[TANJIAHOU]

it wasnt given. :O
we had to find the minimum diameter of a crater, that could be seen using that telescope.

Oh ya. haha. I calculated it instead == Because the angle in degrees is very small, just use circular length formula.

 

[Fatima Iftikhar]

Oh ya. haha. I calculated it instead == Because the angle in degrees is very small, just use circular length formula.

so i did it wrong?

 

[TANJIAHOU]

Its also because the hypotenuse and adjacent sides of a triangle are always of similar lengths whenever we are dealing with angles that are "not very large"

 

[TANJIAHOU]

You did it correctly.. But for small angles, we just use circular formula....

 

[Fatima Iftikhar]

Its also because the hypotenuse and adjacent sides of a triangle are always of similar lengths whenever we are dealing with angles that are "not very large"

but we had to find the diameter, not that circular thingy. so you did it wrong. hehe.

 

[scilove]

it gives arc length. equate to half circumference. get radius and then diameter. small angle approx. didn't work because angle greater than 10 degrees

 

[TANJIAHOU]

greater than 10 degrees??? I'm not so sure about that

 

[Fatima Iftikhar]

greater than 10 degrees??? I'm not so sure about that

it was worth only 3 marks.

 

[TANJIAHOU]

Wow if its 10 degrees, the diameter of the crater is 0.7 * 10^8 m!!!! Far greater than diameter of moon ==

 

[saadgujjar]

Wt abt force between protons question and hall probe graphs...

 

[TANJIAHOU]

but we had to find the diameter, not that circular thingy. so you did it wrong. hehe.

I am right. The arc length is almost equal to the diameter at very small angles. I remember the angle was in the order of 10^-6radians

 

[TANJIAHOU]

The additional force is the strong nuclear binding force between the proton. Short range, because has to counteract effects of electrostatic repulsion.

 

[Fatima Iftikhar]

I am right. The arc length is almost equal to the diameter at very small angles. I remember the angle was in the order of 10^-6radians

yes, you're right probably.

 

[TANJIAHOU]

Hall probe/dc graph: sharp increase then exponential decrease
Hall probe/ac graph: sinusoidal graph

 

[Fatima Iftikhar]

do you bremember your answer to 2nd last question? that ratio?

 

[TANJIAHOU]

Comment on student's suggestion: coil is stationary, so no induced emf or current to calculate magnetic flux density

 

[Fatima Iftikhar]

Comment on student's suggestion: coil is stationary, so no induced emf or current to calculate magnetic flux density

thats exactly what i wrote.

 

[TANJIAHOU]

I forgot == Just use formula la. I = 0.25 Io * exp(-u*x)