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Mr of NaN3=65
Moles of NaN3=0.77
Moles of N2=0.77*3/2=1.15
Volume=1.15*24=27.7 dm^3
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Mr of NaN3=65
Hey bro, will u be available here till 10:00pm IST(Indian Standard Time)..... PLEASE BRO!!!!just for the record if i was being rude who was the one who started it:
I will try but i think this community has more harmony and peace without me.Hey bro, will u be available here till 10:00pm IST(Indian Standard Time)..... PLEASE BRO!!!!
Can u help me with the same year q1Mr of NaN3=65
Moles of NaN3=0.77
Moles of N2=0.77*3/2=1.15
Volume=1.15*24=27.7 dm^3
Suchal Riaz pls solve dis 1Q25) When heated with chlorine, the hydrocarbon 2,2-dimethylbutane undergoes free radical
substitution.
In a propagation step the free radical X• is formed.
2,2-dimethylbutane+ Cl● → X ●+ HCl
How many different forms of X• are possible?
A 1 B 2 C 3 D 4
2NaCl+2H2O----> Cl2+H2+ 2NaOH
q14 A because it is the most electro positive and so it going to draw more negative charges than the other 3 choices will.
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s08_qp_1.pdf
qs 31
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_w08_qp_1.pdf
qs 2 , 31
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s11_qp_11.pdf
qs 24 , 31
ammonium cyanate has ammonia and cynate ionshttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s13_qp_13.pdf
Number 18??? Answer is A
anyone please?
Ally PV=nRT where n= 1/18can u help me solve this
View attachment 45138 ans is c
Moles of H2=0.5Can u help me with the same year q1
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