Mathematics: Post your doubts here!

[iSean97]

Just make argand digram like any simple graph thats it, and plot the points as given.
If u are not asking for this, i am not getting what are u asking for.

9709/32/M/J/16/Q9

because I will not know the position of OA OB OC be like.

How would I know where to pin point my 3 vectors will be?

 

[I Believe]

ii)
Draw haf line with centre at u at angle of pi/4
draw perpendicular from line to origin, and find its distance that is least value of |Z|
iii)
Draw circle with centre (1 + i)u with radius 1. and the distance from origin to the maximum distance of circle is greatest value of |Z|

can you please make it?

 

[Thought blocker]

can you please make it?

9709/32/M/J/16/Q9

because I will not know the position of OA OB OC be like.

How would I know where to pin point my 3 vectors will be?

http://justpastpapers.com/wp-content/uploads/2016/05/scan0107.jpg

 

[iSean97]

View attachment 61203

http://justpastpapers.com/wp-content/uploads/2016/05/scan0107.jpg

Doesn't technically explain my question since it is arranged clockwised, not anticlockwise, or arranged by random for the position of ABCD?
So it doesn't matter?

 

[I Believe]

View attachment 61203

http://justpastpapers.com/wp-content/uploads/2016/05/scan0107.jpg

thank you so much..
so you made the center of circle at 3 - 3i , can you tell me how you got that? sorry for being so dumb but really this thing is confusing me a lot.
And also can you sketch Argand for this too, the (ii) part

 

[Thought blocker]

Doesn't technically explain my question since it is arranged clockwised, not anticlockwise, or arranged by random for the position of ABCD?
So it doesn't matter?

Yes. It doesnt.

 

[Thought blocker]

thank you so much..
so you made the center of circle at 3 - 3i , can you tell me how you got that? sorry for being so dumb but really this thing is confusing me a lot.
And also can you sketch Argand for this too, the (ii) part
View attachment 61204

Oh i didnt get this before :/ idk why.
(1 + i) (- 3i) = 3 - 3i

draw the circle with origin at u and radius being absolute of u.
basically that is asking us to drow locus of |z - (-2/5 + 11/5i)| = sqrt(5)

 

[I Believe]

 

[Thought blocker]

View attachment 61206

Use addittion formulas, and solve it.

 

[I Believe]

Use addittion formulas, and solve it.

I did, but i'm having trouble ... okay tell me
at one point, I get:
2 [cosθ(√3/2) + sinθ(1/2)]
what do we multiply 2 with?
will it be
cos2θ(√3/2) + sin2θ(1/2)
or cosθ2(√3/2) + sinθ 2(1/2) ?
please help

 

[Thought blocker]

I did, but i'm having trouble ... okay tell me
at one point, I get:
2 [cosθ(√3/2) + sinθ(1/2)]
what do we multiply 2 with?
will it be
cos2θ(√3/2) + sin2θ(1/2)
or cosθ2(√3/2) + sinθ 2(1/2) ?
please help

2cosθ(√3/2) + s2inθ(1/2)

 

[I Believe]

2cosθ(√3/2) + s2inθ(1/2)

can this 2 in cosθ be cancelled with the 2 in √3/2? so we get
cos θ √3 + sinθ?

 

[Thought blocker]

can this 2 in cosθ be cancelled with the 2 in √3/2? so we get
cos θ √3 + sinθ?

yes.

 

[I Believe]

yes.

still I get:
sinθ / cos θ = (-1+ √2/2) / [ (2 √3 - √2)/2]
which gets me a totally wrong answer

 

[Thought blocker]

still I get:
sinθ / cos θ = (-1+ √2/2) / [ (2 √3 - √2)/2]
which gets me a totally wrong answer

why wrong?

 

[Thought blocker]

still I get:
sinθ / cos θ = (-1+ √2/2) / [ (2 √3 - √2)/2]
which gets me a totally wrong answer

what is answer?

 

[I Believe]

what is answer?

105.9 degrees

 

[Thought blocker]

105.9 degrees

I got it. Maybe u have done some mistake,
it will be
sin(x)/cos(x) = (-2sqrt(3) + sqrt(2))/(2-sqrt(2))
now u will get it when u add 180 degress to ur x to make it in the domain.

 

[I Believe]

part(i) solution please

 

[Thought blocker]

View attachment 61228
part(i) solution please