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Aymen Ezazi
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  • Q2 B. Number of Moles = 120/24000 = 5x10^-3 moles

    Mr = mass/moles
    Mr = 0.23/5x10^-3
    Mr = 46..

    Now test each one out..

    14x+16y should be 46.. It happens in B.
    14*1+16*2=46
    for Q9
    let X2=A
    Y2=B
    X2y=C
    C^2/(A^2)*B=2
    C^2=2*(A^2)*B
    SQUARE ROOT BOTH SIDES WE GET
    C=(2^0.5)*A*(B^0.5) anything raised to 0.5 means it is square rooted ok
    now for equation 2 we have
    A*(B^0.5)/C
    PUT IN VALUE OF C
    WE GET A*(B^0.5)/(2^0.5)*A*(B^0.5)
    thus we get 1/(2^0.5) as required by question
    (may june 07)for question 6 u need to have an understanding of the hydrogen bonds hten this is very easy. JUst see which one forms hydrogen bonds. Cl cannot form neither can Co2Ch3
    amongst CN and OH we can see that oxygen has more lone pairs than N thus we chose OH
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