• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Recent content by pspwxpfan

  1. P

    HOW WAS PHYSICS PAPER 5 PPL ? HOW WAS YOUR EXAM ?

    Used the following method to approximate the speed of the wind. Thoughts? Position the fan behind a smooth stainless steel surface and place a light object on the surface at a starting position. Use a stopwatch to measure the time taken for it to travel a fixed distance from the starting...
  2. P

    Chem P51 How was it?.

    Guys! The space given for question one was adequate! They didnt want a whole story, they just wanted the four parts to be answered, to the point.
  3. P

    Mathematics: Post your doubts here!

    Can someone tell me how to "simplify the coefficients" of a binomial expansion? For example: 32-32x + 48x^2
  4. P

    Physics MCQs thread.

    Haha yeah, I overlooked the volume part. I should srsly lern2read questions :P
  5. P

    Physics MCQs thread.

    Very interesting. Answer is D?
  6. P

    Physics MCQs thread.

    The most common issue with that is ppl forget that there are two wires, so instead of 800m, 1600m should be taken as the length. This will give 0.005*1600 =8 as total resistance of wire. V=IR will give V=(0.6)(8) =4.8v, which are used in overcoming resistance of the wire. Add this to 16, and...
  7. P

    Physics MCQs thread.

    Draw a rough sketch of the path the ball might have travelled. V=0 at the highest point, so label t=3 at the peak of your sketch. t=5 comes b/w t=3 and ground level. So you will realize that to get displacement from the ground, u need to subtract area b/w t=3 to t=5 from t=0 to t=3.
  8. P

    Physics MCQs thread.

    Let's suppose the current is I. Using parallel/series, P gets I, and Q and are both get I/2. Power across P will therefore be given as I^2*R, and that across Q will be (I/2)^2*R. Same for R. This will simplify to I^2/4*R. So we can see the ratio for the powers across P:Q:R are 4:1:1. Using...
  9. P

    XtremePapers Contest 2010 - 2011!

    Physics AS level-projectile motion ---ADMIN EDIT--- Submission accepted. Ticket: 16564.
See more
Top