wat abt question 2dii)?
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Suchal Riaz
P=Fv so F=P/v
and resolving the forces we get:
F-R=ma
substitute F=P/v
P/v -R = ma
you have found ma in the last part: ma=75N
p/v=ma + R
p/v = 23+75 N
P=(23+75)X(v)
and v = 4.5 m/s
P=(23+75)X(4.5)
and resolving the forces we get:
F-R=ma
substitute F=P/v
P/v -R = ma
you have found ma in the last part: ma=75N
p/v=ma + R
p/v = 23+75 N
P=(23+75)X(v)
and v = 4.5 m/s
P=(23+75)X(4.5)
Suchal Riaz
please post the link of the question from next time.
Snow Angel
ok thank u very much. 
Snow Angel
please can u explain question 2 b) from this paper. can u please draw the sketch and post it? papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_w10_qp_22.pdf
dR = 1/2(dV/V + dL/L)