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  1. GorgeousEyes

    I live for those who love me, for those who know me true; for the heaven that smiles above me...

    I live for those who love me, for those who know me true; for the heaven that smiles above me and awaits my spirit too.
  2. GorgeousEyes

    Mathematics: Post your doubts here!

    could u do the steps if u have time ?
  3. GorgeousEyes

    Sometimes your joy is the source of your smile, but sometimes your smile can be the source of...

    Sometimes your joy is the source of your smile, but sometimes your smile can be the source of your joy .
  4. GorgeousEyes

    Mathematics: Post your doubts here!

    please nov 07 no 3 ii
  5. GorgeousEyes

    Mathematics: Post your doubts here!

    thanks ! :)
  6. GorgeousEyes

    Mathematics: Post your doubts here!

    please jun010 variant 12 :no.10 ii and no.11 iv , v http://papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s10_qp_12.pdf
  7. GorgeousEyes

    Mathematics: Post your doubts here!

    when i tried it my self , i couldn't get c , i don't knw why :S
  8. GorgeousEyes

    Mathematics: Post your doubts here!

    q. 10 -- > x-3squarerootx =10 square root x is half x , so u knw reducing equation to quadritic ? put the equation --> x-3squarerootx-10 on calculator ans = square root x =5 and square root x = -2 but we want x so --> x=(5)2 and x= (-2)^2
  9. GorgeousEyes

    Mathematics: Post your doubts here!

    because the coefficient of x is 2 and the new power is -1 so -1 x 2= -2 .
  10. GorgeousEyes

    Mathematics: Post your doubts here!

    no . 7 : You have to divide the like diamond shape to 2 traingles so u can use tan to get BOT --> -Tan15/8 -- > ans x pi / 180 --- >to get AOB : ans x 2 -- > 2.16 ii . pe :15+15+ 2.16 x8 = 47.28 iii.get the hyp and by it bring tha area of the 2 traingles and subtract it from 2.16 x 8^2 x 0.5...
  11. GorgeousEyes

    Mathematics: Post your doubts here!

    Thanks (y)
  12. GorgeousEyes

    Mathematics: Post your doubts here!

    (6)^2 /(2x-3)^2 so make the integ . --> 36 (2x-3)^-2 -- > 36(2x-3)^-1 / -2 and by using the limits 2 and 3 --> -6-(-18)= 12 pi
  13. GorgeousEyes

    Mathematics: Post your doubts here!

    please jun010 variant 12 :no.10 ii and no.11 iv , v
  14. GorgeousEyes

    Mathematics: Post your doubts here!

    Thanks for ur help :)
  15. GorgeousEyes

    Mathematics: Post your doubts here!

    THANK YOU :)
  16. GorgeousEyes

    Mathematics: Post your doubts here!

    Please Nov2012 v.13 no.6 i . no.7 ii , 8 iii ) , 9 all , 10 iii 11 ) ii and iv urgentlyyy .
  17. GorgeousEyes

    Mathematics: Post your doubts here!

    you should know that tan (180-x) = -tan x .. (1) and tan (90-x) = 1/ tanx .. (2) i) if u used (1) --- > -k ii) use ii --- >1/k iii) by Pythagoras : tan = opp /adj thus tan = k/1 --> so hyp = ksquare+1square under square root so sin =opp /hyp --> so k/= ksquare+1square under square root .
  18. GorgeousEyes

    Mathematics: Post your doubts here!

    Please Nov2012 v.13 no.6 i . no.7 ii , 8 iii ) , 9 all , 10 iii 11 ) ii and iv .. this paper is so hard for me :(
  19. GorgeousEyes

    Mathematics: Post your doubts here!

    How to prepare myself 4 the exam ? :)
  20. GorgeousEyes

    Mathematics: Post your doubts here!

    Thaaanks a millioooon :)
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