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  1. Mehroz

    tanA+cotA= sinA/ cosA + cosA/sinA =sin(square)A+coc(square)A / sinA cosA =2/2 * 1/sinA cosA...

    tanA+cotA= sinA/ cosA + cosA/sinA =sin(square)A+coc(square)A / sinA cosA =2/2 * 1/sinA cosA =2/2sinAcosA (as 2sinAcosA=sin2A) so =2/sin2A
    • Mehroz
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  2. Mehroz

    It is better to light a candle than curse the darkness:)

    It is better to light a candle than curse the darkness:)
    • Mehroz
    • Profile post
  3. Mehroz

    Mathematics: Post your doubts here!

    This is the answer for q3. If you find it useful then just like it:)
  4. Mehroz

    Further Mathematics: Post your doubts here!

    No problem:) just like my posts
  5. Mehroz

    Further Mathematics: Post your doubts here!

    http://www.cimt.plymouth.ac.uk/projects/mepres/alevel/alevel.htm
  6. Mehroz

    Further Mathematics: Post your doubts here!

    first of all solve the equations given y=kx2+1 and y=kx........... this will become kx=kx2+1....then kx2-kx+1=0....... as they do not have a common point so b2-4ac<0 a=k, b=-k, c=1. And solve....
  7. Mehroz

    Mathematics: Post your doubts here!

    Assalamoalaikum.Can anyone help me out in qs 9 part1 os this paper.... http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s10_qp_31.pdf
  8. Mehroz

    Further Mathematics: Post your doubts here!

    Assalamoalaikum to all. Here is a link which might help u all. http://www.cimt.plymouth.ac.uk/projects/mepres/alevel/alevel.htm
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