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  1. U

    in serious problem help required

    one practical is not enough. u shud be able to handle and use the apparatus correctly. atleast 8 to 10 practicals shud be done with the apparatus
  2. U

    Mathematics: Post your doubts here!

    ans 3 {1+[(sin^2)x / (cos^2)x]} / {1 - [(sin^2)x / (cos^2)x]} take the lcm in numerator and denominator respectively {[(cos^2)x + (sin^2)x] / (cos^2)x} / {[(cos^2)x - (sin^2)x] / (cos^2)x} (cos^2)x will be cancelled (cos^2 x + sin^2 x ) / (cos^2 x - sin^2 x) 1 / [(1-sin^2 x) - sin^2 x)] 1 / [1 -...
  3. U

    Mathematics: Post your doubts here!

    ur welcum :)
  4. U

    Mathematics: Post your doubts here!

    locus is {z-(0+3i)} is less than equal to 2. a circle is made with the centre (0,3) with radius 2. the inside of the circle is shaded the other locus is arg z arg {z-(0+0i)} the line is drawn from the origin making tangents with the circle at two points. the line towards right is the one with...
  5. U

    Mathematics: Post your doubts here!

    the circle is the locus (z-u) = 2 {z-(1+2i)} means the coordinate will be 1,2 from where we will originate our locus the line is the locus arg z arg {z - (0+0i)} means the coordinate will be 0,0 from where we will originate our locus the greatest value of angle will be the angle between x-axis...
  6. U

    Physics: Post your doubts here!

    ur welcum but im not bro. m a grl :p
  7. U

    Physics: Post your doubts here!

    power dissipation by direct current will be (Irms^2)*R where Irms will be Io power dissipation by sinusoidal current will be (Irms^2)*R where Irms will be Io/(square root of 2) [(Io^2) * R] / {[(Io/sqr root of 2)^2]*R} Io^2*R will be cancelled inverse of (2) will be left inverse of 2 will be 2...
  8. U

    Physics: Post your doubts here!

    im really sorry. i dun know any other way
  9. U

    Physics: Post your doubts here!

    the activity A0 is stated with 2% error. we hav to get the time for 10% ka error. means original se 8% error. if original is A0, then after 8% error, it will be 0.92A0. we will consider the expression: A = A0* e^(-lambda*time) lambda will be 0.693/half life lambda = 0.693/(5.27*365*24*3600) A =...
  10. U

    Physics: Post your doubts here!

    m getting 236 days. but marking scheme main 230 days hai :unsure:
  11. U

    Physics: Post your doubts here!

    p.d divides in series, not in parallel. each branch will hav p.d of 2V. the first branch has resistors in 1:1 ratio so p.d will be equally divided. each resistor of 5 ohms will hav p.d of 1V. so v1 is 1V. in the second branch, the resistors are in the ratio 2:3. the p.d in the 3 ohms resistor...
  12. U

    Physics: Post your doubts here!

    part a or b?
  13. U

    Physics: Post your doubts here!

    m a grl.... i think u have done the last part correct, but i think the second part is wrong. it shud b as i have done it... cox in 2nd part, gradient is increasing while in last part it is constant so it will b a straight line
  14. U

    Physics: Post your doubts here!

    ur welcum :)
  15. U

    Mathematics: Post your doubts here!

  16. U

    Mathematics: Post your doubts here!

    i) higher than the top of the tower means higher than 25 m. from ground to top of tower means till 25 m, we hav the info as: u = 30 m/s v1 = ? s = 25 m a = -10 apply the formula 2as = v1^2 - u^2 2 (-10) (25) = v1^2 - (30)^2 v1 = 20 m/s from top of tower to the maximum height the info is: v1...
  17. U

    Mathematics: Post your doubts here!

    answers milenge plx?
  18. U

    Physics: Post your doubts here!

  19. U

    Physics: Post your doubts here!

    emf = change in magnetic flux linkage per unit time = NBA/t N, A and t are constant B is changing. emf is directly proportional to -B (lenz's law) B= F/IL B is inversely proportional to I means emf is negative gradient of I the graph is divided in 4 parts in the first part, I is zero, so there...
  20. U

    Physics: Post your doubts here!

    ur welcum :)
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