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Search results

  1. Anum96

    Sweet as sugar and everything nice..

    Sweet as sugar and everything nice..
  2. Anum96

    Take care <3

    Take care <3
  3. Anum96

    Achhh. :p

    Achhh. :p
  4. Anum96

    Ura lu mazak tum :p

    Ura lu mazak tum :p
  5. Anum96

    I know right. Thats exactly how I am most of the time :p

    I know right. Thats exactly how I am most of the time :p
  6. Anum96

    Hahahaha! :D Oh, yes! *_*

    Hahahaha! :D Oh, yes! *_*
  7. Anum96

    HAHAHAHA. :p Its a picture from the movie 'Julie and Julia' So I was really very much certain :p

    HAHAHAHA. :p Its a picture from the movie 'Julie and Julia' So I was really very much certain :p
  8. Anum96

    Done. :p

    Done. :p
  9. Anum96

    Really? O-O She's having coffee :3

    Really? O-O She's having coffee :3
  10. Anum96

    You'll pay for it sooner or later. Simple xD

    You'll pay for it sooner or later. Simple xD
  11. Anum96

    Wait.... Don't you dare!

    Wait.... Don't you dare!
  12. Anum96

    Yo, peace :p

    Yo, peace :p
  13. Anum96

    Anytime :)

    Anytime :)
  14. Anum96

    ^You landed on a wrong post.

    ^You landed on a wrong post.
  15. Anum96

    True.

    True.
  16. Anum96

    ^^ Yeah, and they call it winning. ^ :sigh:

    ^^ Yeah, and they call it winning. ^ :sigh:
  17. Anum96

    Half of the population just waitin' to see me fail...

    Half of the population just waitin' to see me fail...
  18. Anum96

    800*-0.1 *equals* 10(1-1.1^n) -80/10 *equals* 1-1.1^n -8-1 *equals* -1.1^n -9 *equals* -1.1^n...

    800*-0.1 *equals* 10(1-1.1^n) -80/10 *equals* 1-1.1^n -8-1 *equals* -1.1^n -9 *equals* -1.1^n 1.1^23 *equals 8.95 N must be 23 :)
  19. Anum96

    It is g.p. Sorry about that. I misread it. First term is 10 Common ratio is 1.1 And so you have...

    It is g.p. Sorry about that. I misread it. First term is 10 Common ratio is 1.1 And so you have 800 *equals* 10(1-1.1^n)/1-1.1
  20. Anum96

    a is 10 The common difference is 1.2 So we have the formula s(of all terms)*equals* n/2(2a...

    a is 10 The common difference is 1.2 So we have the formula s(of all terms)*equals* n/2(2a *plus* (n-1)d) 800 *equals* n/2 (2(10) *plus* (n-1)1.2)
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