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  1. E

    Physics Oct/Nov 2010 P43 q3 (A) i - Help needer

    Since in the equation we have the amplitude as -4......and -4 corresponds to lowest postion........-4x2 the max height...=8
  2. E

    discussion of physics ppr 2 AS

    hmmm..i got it wrong..1.1 shud be the answer...My working is right...i also used a=+9.8..... B/w the answer was 25sin(35)....Tension ki line ko backward extend karna tha...Move the 25 newton force and make a closed triangle...With simple geometry the answer would work out to be 14. something....
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    discussion of physics ppr 2 AS

    who cares...
  4. E

    discussion of physics ppr 2 AS

    It doesnt matter...answer would work out the same...
  5. E

    discussion of physics ppr 2 AS

    800 ohm was the old net resistance b/w point A and B and i got 960 ohm as the new resistance b/w A and B ...The resistance of thermistor would be therefore 2400 ohm and temperature 11 degree celcius....
  6. E

    discussion of physics ppr 2 AS

    Thats what i am saying. It said it took the ball o.17s to just cross the wall. U should check at what time it would reach the max height. It could also go above that height of the ball. I am sure i have done right(can have some calculation mistake)....Because there is a huge difference b/w just...
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    discussion of physics ppr 2 AS

    sorry not the height of ball. I meant wall
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    discussion of physics ppr 2 AS

    The height of the ball is 1.38....u cant use v^2=u^2+2as.....Because it didnt say that at that height the ball was at its max height or final vertical velocity is zero. U have to use T=0.17 s. and this equation s=ut+1/2at^2...Horizontal distance was 1.7 m and height was 1.38 m. On the other...
  9. E

    Got Everything Coming For Chem Paper 34! :)

    please pm me too. I wil pray 4 ur distinctions.
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