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  1. PlanetMaster

    !!!LOST STATEMENT OF ENTRY PLZ HELP!!!

    Contact British Council immediately! They'll ask you to take an appointment first but go directly without an appointment. They'll give you a letter for current exam which can be used as an alternate.
  2. PlanetMaster

    urgent!! help in maths extended

    Nope! :)
  3. PlanetMaster

    Which Calculators are Allowed???

    Officially speaking Fx-570/991 with or without any suffix are prohibited but they can be taken into exams without any issue. Obviously you have to show working but you may use them to verify your answers for differentiation and integration etc.
  4. PlanetMaster

    urgent!! help in maths extended

    The formula is given n(n +1)/2 Using this formula for (n+1) = [(n +1)(n + 2)]/2 Sum of the nth and the (n+1)th terms: = n(n +1)/2 + [(n +1)(n + 2)]/2 = (n+1)²
  5. PlanetMaster

    Sequence problems?? I got a solution...

    The formula is the same. The common ratio is squared or cubed. I don't think that geometric progression is in IGCSE syllabus but it many marking schemes, the method shown is geometric progression.'' I'm aware of that! Its a routing problem due to maintenance. Replacing server's can take more...
  6. PlanetMaster

    Calculator for olevel

    Yes! Fx-570ES/MS and Fx-991ES/MS both can do differentiation and integration and are allowed.
  7. PlanetMaster

    Calculator for olevel

    It should be non-graphical and non-programmable. All Casio MS & ES are allowed which includes you Fx-991MS.
  8. PlanetMaster

    Sequence problems?? I got a solution...

    This is a geometric progression. A geometric progression is a sequence where each term is r times larger than the previous term. r is known as the common ratio of the sequence. The nth term of a geometric progression, where a is the first term and r is the common ratio, is ar^(n-1) For example...
  9. PlanetMaster

    Biology Paper 31

    Any discussion related to paper leak is agains't 'XPF Rules' :!:
  10. PlanetMaster

    Mathematics extended..

    CIE only published '2009 Specimen Paper 4' which can be downloaded from: QP: http://www.xtremepapers.net/CIE/index.p ... _sp_4a.pdf MS: http://www.xtremepapers.net/CIE/index.p ... _sm_4a.pdf
  11. PlanetMaster

    Phiscis Paper1 M/J 2007 and O/N 2007

    May/June 2007 Paper 1: Question 16: At position 3, the rope is stretched at maximum so there's no movement therefore Kinetic energy will be minimum. The elastic being stretched out at maximum makes elastic potential energy maximum. So its 'C'. Question 17: Density of P > Density of Q (Given)...
  12. PlanetMaster

    suggestion

    It's a great idea! :) But if someone specifically want's a marking scheme, he/she will need to download the entire compressed file. Let's just not forget that we still have over 30% of viewers using dial-up. Many viewers are also using mobile phones which can handle pdf's but handling zip's...
  13. PlanetMaster

    URGENT!! PLZ HELP!!!

    Right click the file(s), and click 'Save target as..' or 'Save link as..'. Once downloaded, then try opening the file. What's the error generated?
  14. PlanetMaster

    Any clue for Further Mathematics P1

    But the paper starts according to GMT time! Best of luck. :)
  15. PlanetMaster

    URGENT!! PLZ HELP!!!

    I've checked the links. They are perfectly opening!
  16. PlanetMaster

    physics mcqs HELP !

    I guess that paper isn't in our download section. Can you provide the question?
  17. PlanetMaster

    MATH HELP URGENT!!!!!!!!!!

    0581 May/June 09 Q6a(ii): x² + 5x – 36 = 0 x² + 9x - 4x - 36 = 0 x(x+9) - 4(x+9) = 0 (x+9)(x-4) = 0 0581 Oct/Nov 08 Q5(e): You need to calculate horizontal distance of A to C: =60sin35 + 40sin80 =73.81km 0581 Oct/Nov 08 Q10c(ii): Its a simple 'Arithmetic Progression'. Use the formula for sum...
  18. PlanetMaster

    New Themes

    Don't worry. This theme isn't going anywhere. :)
  19. PlanetMaster

    Help ! MAth Nov 08 P4 , A Stupid Sequence Problem !

    Come on we are here to help and that's exactly what I'm going to do. 8-) Its a simple 'Arithmetic Progression'. Use the formula for sum of terms: S(n) = (n/2) * [2a + (n-1)d] S(n) = (n/2) [2 + 2(n-1)] S(n) = n² Clear?
  20. PlanetMaster

    Dear Admins

    Go ahead.
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