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Mathematics: Post your doubts here!
kx - 4 = x^2 - 2x x^2 - 2x - kx + 4 = 0 x^2 - x (2 + k) + 4 = 0 Use b^2-4ac = 0 (Discriminant = 0 as curve intersects at two distinct points) k^2 + 4k + 4 - 16 = 0 hence, k > 2 and k < -6 :)- Thought blocker
- Post #13,563
- Forum: A-Levels
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Mathematics: Post your doubts here!
At x = 3 there is line of symmetry so A = x value so 1 is given zero and from 2(x-3)^2-5 we get A as 3 but we have 2 out the bracket hence A=6- Thought blocker
- Post #13,562
- Forum: A-Levels
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SOLVED HARDEST questions for QUICK last day REVISION
Ty ty :P- Thought blocker
- Post #105
- Forum: A-Levels
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SOLVED HARDEST questions for QUICK last day REVISION
Remember me? :P- Thought blocker
- Post #103
- Forum: A-Levels
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|вєѕт яєνιѕιση яєѕσυя¢єѕ ƒσя ρнуѕι¢ѕ, ¢нємιѕтяу αη∂ мαтнємαтι¢ѕ (ѕ¢αηηє∂ ρυяє мαтн вσσкѕ υρℓσα∂є∂)|
Bhai aap kab compilation karne wale ho? Aap or shoaib672002 ? Waiting for that. :D- Thought blocker
- Post #46
- Forum: A-Levels
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