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  1. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Ah, dem Brits with their tea. *accepts* *takes tea to study table* Physics time now, l8r :P
  2. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Nope, I thought of it too. *high 5*
  3. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Hahah, true. Or, more likely, a cerebral infarction, when we can't even think straight :D
  4. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    I see your point bro. True that. However, I know for a fact that the Cambridge system is better than the national system we have, so I guess I'm kinda grateful for what I have :)
  5. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    YES EXACTLY what I asked as well! If I get a satisfactory answer to that, I'll be satisfied. Anyway, off to revise Physics now....Good luck to y'all :)
  6. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    So...you are saying we are acting uncivilized? Aww....:/
  7. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Hey, at least it's a civilized civil war? *ba dum tss* :P
  8. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Good point, I really should get back to Physics now...
  9. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    T is the total time the particle traveled, considering both the variable and non-variable regions. They said, it reached A at T=8. And then find distance from T=0 to T=27. So T is the time for the entire motion of the particle. :)
  10. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Ah, the cruelty of M1 exams...*sigh* :P
  11. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Brother! Finally I get a matching logic :X3:
  12. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Yes, that's perfectly right. So, let me just ask this. If you were to consider the bounds as 8s and 0s, instead of 27 and 8 (just hypothetically saying), what time's distance are you calculating? Can you tell me the answer to that? :)
  13. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Haha, let's just calm down for a second now. The first part is perfectly fine, for first 8 seconds, distance is 8m BUT, if we consider the equation, it only became active after reaching A, which was reached after T=8. So, what distance are you removing when you consider for s(8)? If we put in...
  14. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    yeah, I guess so. Oh well :P
  15. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Ok, first they said the particle has linear acceleration of 0.25 ms-2 until it reaches point A, at T=8. After that point, the particle has a non-linear acceleration, shown by the equation of v. SO that equation of v was applicable ONLY after the particle had reached point A at t=8. Now, let us...
  16. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Ok, guys, lets just calm down, I'll try and explain why the answer is not 71.3 in the next post.
  17. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    I have no idea, but the question was just 1 mark...so :/
  18. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Question about stone was discussed someplace in pages 5 or 6 I believe. R was 15.5 (I think, forgot exact), and T was 17.59 (maybe, again, forgot exact). If question 2 is the collision question, I think the T is 5s.
  19. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    Whoopee, glad mine matches with someone else! (y) Now I just hope we're correct...
  20. wizteddy13

    Mechanics 1 P42 2014; Discussion!

    I freaked out when I saw that one...the wall of text is such a deterrent.
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