Search results

haha. Too late you were :p

You're welcome. :)

two people want to sit on opposite side. They can do this in 2P2 ways or 2! There are 4 seats to choose from or in other word there are 4C1 seats the first person can choose to sit on one seat of the opposite side & 4C1 choices for the second person who wishes to sit on the opposite side...

(4C1)(4C1)*2P2*3P2*4P4 = 4608

Answer?

Make factors. 3x^2 - 21ax - ax + 7a^2 3x(x - 7a) - a(x - 7a) (3x - a) (x - 7a) x is a/3 & x is 7a Now Put signs accordingly :)

Lums only accepts applications once a year between nov and feb I guess. O_o

http://lums.edu.pk/event-details.php/lums-open-day-on-sunday-december-20-2015-3763 Is anyone out here planning to go?

Yes, Apparently... Never doing a part alone again

Nothing. I dont even read the whole question properly. Its a straight 11 mark qs :unsure:

:unsure::unsure:

The question says least 'positive'

Ohh, I just memorized the iii part and did it. Didnt bother reading the first 2 Sorry

Well, I cant be 100 % sure here, but here's what I did. Greatest value of cosine is 1. You will get that when 1/2(theta) is 360 greatest value of sin is also 1. You will get that when 1/2(theta) is 90 Therefore plugging in 1 will give you 7 plus 5 plus 12 which is 24 Now 24 is the greatest value...

Sure. Wait up Whats the answer ? I'll post if I get it correct

http://www.mathcentre.ac.uk/resources/uploaded/mc-ty-rcostheta-alpha-2009-1.pdf Use these notes for these type of questions. You will find what u need in the last heading that's all about maximum and minimum values :)

People like me loveee long cuts :3 First find the common ratio. 40:4:15 X:5:6 40(1:0.1:0.375) X:5:6 Now equate the second ratio to find x 5/x = 0.1 6/x = 0.375 You will get x = 50 and x = 16 Find the commonly shared value of x 50/16 = 3.125 Multiply by 40 to find the no. of men...