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Further proof, from an actual question... Question 2. I'll paste the words here too: Aqueous lead(II) nitrate and aqueous potassium iodide are added to a dish containing water, as shown. A yellow precipitate forms after a few minutes.

Nobody will have done Var 1.. People may be taking Var 2 soon though, but it's not a lot to go on to be honest.

19 is B for sure. The yellow ppt shows us that iodine is present, and thus B is the only acceptable answer.. On another note, I completely agree with Cap'n above me.. It is the reactant, not the product they ask for.

It is B. Simply because of what you said, the MgO is too reactive to be reduced.. The carbon will not react with the air no..

The answer is: And basically, because it is ionic, and the only soluble ionic there :D

Chlorine isn't acidic, it bleaches all indicators white or off-yellow.. The answer is D because the indicator at the anode is colourless, and the indicator at the anode turns blue/purple as NaOH is formed, due to the removal of H at the cathode. Hope I helped, best of luck tomorrow :D

Cyprus, yourself?

Yahh :D Started again yesterday :P Good luck to you too good fellow :D

The 2nd one.. You need to show the other bonds, brackets, and the n outside, to show that it is a repeat unit.

36 is D, and 19 is B, As yousef already said. If you need further explanation, just ask (:

On another note, what you wrote is correct :D

Dude, I have to admit, I have never been so worried.. I almost had a heart attack on the spot... I was running around and talking to my friends like, OMG, Did I forget a page??!?!?!?!

There wasn't that question in variant 1 :S

Neither dissolve in water or acid.. They react with acid. Your first test is right for distinguishment, as Water is produced in the ZnO reaction.

Do not believe so.. It's a simple non-metal after all.