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MCQ's are epic

your welcome! let me know if u need help in any other :)

Q22- E=F*l/A*extension A= (2.5*10^-4)^2 * pi then substituting all values find l/extension. then find its reciprocal. then *100 to get %. Q26- d=1/N. N=300000 per m 1/N=n*lambda n will be 7 then times 2 u get 15 :)

sorry typing error! i meant + not * :) yes xylem is appoplast

check this example :) tell me if i should elaborate

no problem :)

the qstns i anwered in the other post. For the image last question - 1st find the current. total R=7.5 then 2/7.5=0.26A. as it is parallel circuit current gets divided so 0.26/2=0.13 or 2/15 for easier calculation. then find V across X. V=IR = (2/15)*5 = 2/3V then find V across Y. (2/15)*10 =...

Q16- phosphate and hydrophilic head occupies less space. Hydrocarbon chains are large and have a chain structure. Q29- xylem is dead. heating will not affect it. only phloem will get affected. Q30- xylem will be affected 1st. water moves through xylem and its the appoplast pathway. so if fungi...

Thats if you get really low in those papers or score the minimum value of an A in individual papers. I know many people who achieved an overall A* even after getting an E in P3 or P5 and some haplessly got U but still managed to attain an A*. Thats why i mentioned doing extremely well in P2 and P4

make 81 in the power of 3. u get 3^4=81. so X=3

we expected the ratio to be 1:3. 40+72=112 total offsprings. so according to the ratio we expected 28:84 offsprings

For Q11 - for A XYn-->X + nY there are n X-Y bonds in the molecule. Enthalpy change is the energy needed to break these n bonds. They all break and form atoms of X and Y. So dividing the enthalpy by n we get the energy for one bond.

because when the double bond broke, the C was bonded to only one other C and one H and double bonded to an O which is a CHO group of aldehyde. Always just join an O atom whenever u break a double bond using KMnO4. then check if the C is bonded to 1 or 2 other C. If its bonded to 1 C then make an...

You have been helped already..maybe next time ;)

Q1- P is 2k and Q is k. For the same force applied, P will have extension of 2X and Q will have extension X (as k and extension are directly proportional when F is constant) so work done=Force*distance. they have same force so for P work done=F*2X and Q=F*X. hence work done by P will be twice of...

Q14- A because max height means it covered half the distance so the energy also gets halved. Q16- C. first find input power. output/input *100=efficiency. so 400000000/80=5MW then find I using P=IV, 5MW/25kV=200A Q21- find the area under the graph. Make it a triangle 1st...

Q24- X is not a hydrocarbon as hydrocarbons dont react with PCl5. X can either be acid or alcohol but we cant still distinguish which one it is. X is not an aldehyde for sure as X does not react with 2,4-dinitrophenylhydraxine. So we cant be sure whether its an alcohol or acid but we can say...

F=change in momentum/time change in momentum is p1-p2 and the time taken is t2-t1

A and B have H-bonds as well. In D Vander Waals forces are becoming stronger as its solidifiacation. In C there are only Vander Waals forces and its melting so the bonds need to be overcome.

Q2- if it had constanr acceleration it would keep going up and wouldnt come down. Q8- F=ma so a=F/m F and m are constant so a will also be constant. Q11- mercury is denser than water so it wont move much so h will be less :)